This entry lowers the sufficient exponent cutoff for the sharp diagonal Hlawka formula from 63 to 62. For every real , the foundation's unchanged cyclic constant is the least constant comparing the triple deficit with the pair-deficit sum for every complex coordinate triple in every finite dimension.
The statement includes unequal and zero input vectors and dimension zero. It concerns complex diagonal matrices through their coordinate norms. It does not settle the conjectured cutoff 2 or the full noncommutative matrix problem.
The confinement radius on this integer is . The accepted cutoff- theorem remains the tail this argument calls. Cutoffs 64, 65, 66, and 70 stay proved and are not restated here.
This is the last integer this confinement argument reaches. At every radius whose tangent model stays positive already makes the budget- box factor larger than .
theorem HlawkaSchatten.DiagonalCutoff.cutoff62 :
∀ p : ℝ, 62 ≤ p →
IsLeast {C : ℝ | ∀ n : ℕ,
HasHlawkaConstant (lpNorm p : (Fin n → ℂ) → ℝ) C}
(cyclicConstant p) := by sorryFor every real exponent , let be the foundation's finite coordinate -norm and let be its unchanged cyclic constant, the supremum of the cyclic ratio over .
Then is the least real constant such that the triple deficit is at most times the pair-deficit sum, for every natural-number dimension and all complex vectors in that dimension.
This combines admissibility and optimality uniformly over all finite complex coordinate dimensions, including dimension zero and triples with unequal or zero norms. The accepted cutoff- theorem covers every . This statement is the same leastness claim from upward.
Formalization Note. The statement is IsLeast of the set of uniform complex HasHlawkaConstant bounds, with least element cyclicConstant p.
No open leaves. Every sub-goal is proved or awaiting decomposition.