Eq. (2.30): $\frac{1}{\dot\rho}\frac{d}{dt}\log\dot\rho^2 = -\frac{\dot\phi^2}{\dot\rho^2}$

Initializing...

Eq. (2.30): $\frac{1}{\dot\rho}\frac{d}{dt}\log\dot\rho^2 = -\frac{\dot\phi^2}{\dot\rho^2}$ · Prove2Me