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Exact number of ordered disjoint-subset pairs with fixed union

Proved
ThreeSum.LayerCounts.unionFiber_card

by wurtle · Oct 14, 2026 · Mathlib 0df444a (Lean v4.33.1)

3sumalgorithmsfine-grained-complexitythree-sum-1962word-ram

Let L,h∈NL,h\in\mathbb NL,h∈N and let Q⊆{0,…,L−1}Q\subseteq\{0,\ldots,L-1\}Q⊆{0,…,L−1} have cardinality 2h2h2h. The number of ordered pairs of disjoint hhh-element subsets whose union is QQQ is

∣{(S,T):∣S∣=∣T∣=h, S∩T=∅, S∪T=Q}∣=(2hh).\bigl|\{(S,T):|S|=|T|=h,\ S\cap T=\varnothing,\ S\cup T=Q\}\bigr| =\binom{2h}{h}.​{(S,T):∣S∣=∣T∣=h, S∩T=∅, S∪T=Q}​=(h2h​).

The pairs are ordered, so exchanging the two subsets is not identified. The statement includes the empty case h=0h=0h=0.

This gives the exact number of graph representations of a single output subset, a quantity used in the local hash-cover counting estimates.

Preamble
import Definitions.Def_ThreeSum1962Source_Bundle01
import Lean.Elab.Tactic.Omega
import Mathlib.Algebra.BigOperators.Group.Finset.Basic
import Mathlib.Data.Finset.Powerset
import Mathlib.Data.Finset.Prod
import Mathlib.Data.Fintype.Card
import Mathlib.Data.Nat.Choose.Basic


set_option autoImplicit false
set_option relaxedAutoImplicit false
set_option Elab.async false

Formal statement
theorem ThreeSum.LayerCounts.unionFiber_card : ∀ {L h : Nat} (Q : Finset.{0} (Fin L))
  (hQ :
    @Eq.{1} Nat (@Finset.card.{0} (Fin L) Q)
      (@HMul.hMul.{0, 0, 0} Nat Nat Nat (@instHMul.{0} Nat instMulNat)
        (@OfNat.ofNat.{0} Nat (nat_lit 2) (instOfNatNat (nat_lit 2))) h)),
  @Eq.{1} Nat
    (@Finset.card.{0} (Prod.{0, 0} (Finset.{0} (Fin L)) (Finset.{0} (Fin L)))
      ({p ∈ ThreeSum.LayerCounts.edgeSet L h |
        @Eq.{1} (Finset.{0} (Fin L))
          (@Union.union.{0} (Finset.{0} (Fin L)) (@Finset.instUnion.{0} (Fin L) (instDecidableEqFin L))
            (@Prod.fst.{0, 0} (Finset.{0} (Fin L)) (Finset.{0} (Fin L)) p)
            (@Prod.snd.{0, 0} (Finset.{0} (Fin L)) (Finset.{0} (Fin L)) p))
          Q}))
    ((@HMul.hMul.{0, 0, 0} Nat Nat Nat (@instHMul.{0} Nat instMulNat)
          (@OfNat.ofNat.{0} Nat (nat_lit 2) (instOfNatNat (nat_lit 2))) h).choose
      h) := by
  sorry
Source
https://github.com/c0ldzy17/three-sum-lean/blob/2b639655e07421b9ac743de9090459bab473a7c0/Submission/ThreeSum/LayerCounts.lean#L83-L107

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