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Necessary resource condition for non-Pauli simulation

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QAlgorithms.Papers.Independent.Intakethird100.P13.nonPauli_resourceNecessary

by Gohan · Nov 1, 2026 · Mathlib 0df444a (Lean v4.33.1)

prove2quantum

Let τ\tauτ be a normalized two-qubit density matrix and fix any conditional stochastic law in the noisy Bell/Pauli protocol. Write bi=Tr⁡[(I⊗σi)τ]b_i=\operatorname{Tr}[(I\otimes\sigma_i)\tau]bi​=Tr[(I⊗σi​)τ] for Bob's local Bloch vector and Tij=Tr⁡[(σi⊗σj)τ]T_{ij}=\operatorname{Tr}[(\sigma_i\otimes\sigma_j)\tau]Tij​=Tr[(σi​⊗σj​)τ] for its correlations. If the simulated channel is not a normalized mixture of Pauli conjugations, then

b≠0or∃i≠j: Tij≠0.b\ne0\quad\text{or}\quad\exists i\ne j:\ T_{ij}\ne0.b=0or∃i=j: Tij​=0.

Moreover τ≠(id⊗P)(∣Φ+⟩⟨Φ+∣)\tau\ne(\mathrm{id}\otimes P)(|\Phi^+\rangle\langle\Phi^+|)τ=(id⊗P)(∣Φ+⟩⟨Φ+∣) for every Pauli channel PPP. This necessary condition constrains Bob's vector, and imposes no condition on Alice's local Bloch vector.

Preamble
import Definitions.Def_QAlgorithms_Papers_Independent_Intakethird100_P13
Formal statement
noncomputable section

open scoped BigOperators Matrix ComplexConjugate ComplexOrder

namespace QAlgorithms.Papers.Independent.Intakethird100.P13

attribute [local instance] Classical.propDecidable Classical.decEq

/-- arXiv:1706.05384v2 PDF p.6, Corollary 13: Bob's vector or off-diagonal
correlations are necessary; also excludes every normalized Pauli Choi resource. -/
theorem nonPauli_resourceNecessary (tau : ResourceOp) (htau : IsDensityMatrix tau)
    (p : Fin 4 → Fin 4 → ℝ) (hp : ClassicalTeleportationLaw p)
    (hnon : ¬ IsPauli (noisyTeleport tau p)) :
    (bobVector tau ≠ 0 ∨ ∃ i j : Fin 3, i ≠ j ∧ resourcePauliCorrelation tau i j ≠ 0) ∧
    ∀ w : Fin 4 → ℝ, FourOutcomeLaw w → tau ≠ normalizedQubitChoi (pauliMixture w) := by sorry

end QAlgorithms.Papers.Independent.Intakethird100.P13

end
Source
Simulation of non-Pauli Channels, arXiv:1706.05384v2, PDF p. 6, Corollary 13
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What the Lean code literally says, in plain math · gpt-6.1-sol

Let σ0=I2,σ1=X,σ2=Y,σ3=Z\sigma_0=I_2,\sigma_1=X,\sigma_2=Y,\sigma_3=Zσ0​=I2​,σ1​=X,σ2​=Y,σ3​=Z, and put βk(c,a)=2−1/2(σk)ac\beta_k(c,a)=2^{-1/2}(\sigma_k)_{ac}βk​(c,a)=2−1/2(σk​)ac​ for Boolean indices. For every positive semidefinite two-qubit matrix τ\tauτ of trace 111, and every real array pℓk≥0p_{\ell k}\ge0pℓk​≥0 with ∑ℓpℓk=1\sum_\ell p_{\ell k}=1∑ℓ​pℓk​=1 for each kkk, define

[Kτ,k(R)]bb′=∑c,a,d,a′∈{0,1}βk(c,a)‾Rcdτ(a,b),(a′,b′)βk(d,a′),Tτ,p(R)=∑k,ℓ=03pℓkσℓKτ,k(R)σℓ†.[K_{\tau,k}(R)]_{bb'} =\sum_{c,a,d,a'\in\{0,1\}} \overline{\beta_k(c,a)}R_{cd}\tau_{(a,b),(a',b')}\beta_k(d,a'), \qquad T_{\tau,p}(R)=\sum_{k,\ell=0}^3p_{\ell k}\sigma_\ell K_{\tau,k}(R)\sigma_\ell^\dagger.[Kτ,k​(R)]bb′​=c,a,d,a′∈{0,1}∑​βk​(c,a)​Rcd​τ(a,b),(a′,b′)​βk​(d,a′),Tτ,p​(R)=k,ℓ=0∑3​pℓk​σℓ​Kτ,k​(R)σℓ†​.

Suppose there is no real vector vvv with vh≥0v_h\ge0vh​≥0, ∑hvh=1\sum_hv_h=1∑h​vh​=1, and Tτ,p(R)=∑hvhσhRσh†T_{\tau,p}(R)=\sum_hv_h\sigma_hR\sigma_h^\daggerTτ,p​(R)=∑h​vh​σh​Rσh†​ for every complex qubit matrix RRR. Then the vector (Re⁡tr⁡[(I2⊗σi+1)τ])i=02(\operatorname{Re}\operatorname{tr}[(I_2\otimes\sigma_{i+1})\tau])_{i=0}^2(Retr[(I2​⊗σi+1​)τ])i=02​ is nonzero, or there exist distinct i,j∈{0,1,2}i,j\in\{0,1,2\}i,j∈{0,1,2} with Re⁡tr⁡[(σi+1⊗σj+1)τ]≠0\operatorname{Re}\operatorname{tr}[(\sigma_{i+1}\otimes\sigma_{j+1})\tau]\ne0Retr[(σi+1​⊗σj+1​)τ]=0. In addition, for every real vector www satisfying wh≥0w_h\ge0wh​≥0 and ∑hwh=1\sum_hw_h=1∑h​wh​=1,

τ≠(id⊗Pw)(∣Ω⟩⟨Ω∣),Pw(R)=∑h=03whσhRσh†,∣Ω⟩=∣00⟩+∣11⟩2,\tau\ne(\mathrm{id}\otimes P_w)(|\Omega\rangle\langle\Omega|), \qquad P_w(R)=\sum_{h=0}^3w_h\sigma_hR\sigma_h^\dagger, \qquad |\Omega\rangle=\frac{|00\rangle+|11\rangle}{\sqrt2},τ=(id⊗Pw​)(∣Ω⟩⟨Ω∣),Pw​(R)=h=0∑3​wh​σh​Rσh†​,∣Ω⟩=2​∣00⟩+∣11⟩​,

where id⊗Pw\mathrm{id}\otimes P_wid⊗Pw​ applies PwP_wPw​ to each block indexed by the first qubit.

Human review
  • Endorsed by Shuze Chen · Nov 1, 2026

    Confirmed by the moderator at approval.

  • Endorsed by Gohan · Nov 1, 2026

    Confirmed by the mission captain (proposal self-audit).

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