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A map with small image on a whole star has a common hole with every map (Erdős 624)

Proved
Erdos624.core_compression_surplus

by Ethan Cheung · Oct 24, 2026 · Mathlib 0df444a (Lean v4.33.1)

combinatoricserdos-problems

Let UUU be a finite set with n=2kn=2^kn=2k elements. For a map g:P(U)→Ug:\mathcal P(U)\to Ug:P(U)→U and Y⊆UY\subseteq UY⊆U write Ig(Y)={g(A):A⊆Y}I_g(Y)=\{g(A):A\subseteq Y\}Ig​(Y)={g(A):A⊆Y}. For B⊆UB\subseteq UB⊆U let KB\mathcal K_BKB​ be the set of kkk-subsets Y⊇BY\supseteq BY⊇B.

Theorem. Let k≥3k\ge3k≥3, S⊆US\subseteq US⊆U with ∣S∣≤k−2|S|\le k-2∣S∣≤k−2, and let h:P(U)→Uh:\mathcal P(U)\to Uh:P(U)→U satisfy 64∣Ih(Y)∣≤n64|I_h(Y)|\le n64∣Ih​(Y)∣≤n for every Y∈KSY\in\mathcal K_SY∈KS​. Then for every map g:P(U)→Ug:\mathcal P(U)\to Ug:P(U)→U,

n ∣KS∣  ≤  64∑Y∈KS(n−∣Ih(Y)∪Ig(Y)∣).n\,|\mathcal K_S|\;\le\;64\sum_{Y\in\mathcal K_S}\bigl(n-|I_h(Y)\cup I_g(Y)|\bigr).n∣KS​∣≤64Y∈KS​∑​(n−∣Ih​(Y)∪Ig​(Y)∣).

In particular hhh and ggg have a common hole on some kkk-set through SSS. Context: Erdős Problem 624 asks whether H(n)−log⁡2n→∞H(n)-\log_2 n\to\inftyH(n)−log2​n→∞, where H(n)H(n)H(n) is the least mmm such that some f:P(X)→Xf:\mathcal P(X)\to Xf:P(X)→X (∣X∣=n|X|=n∣X∣=n) satisfies f[P(Y)]=Xf[\mathcal P(Y)]=Xf[P(Y)]=X for all ∣Y∣≥m|Y|\ge m∣Y∣≥m. By an earlier track-amplification result it would suffice to show that, for large kkk, any two maps P(U)→U\mathcal P(U)\to UP(U)→U with ∣U∣=2k|U|=2^k∣U∣=2k have a common hole: a kkk-set YYY and a point uuu missed by both maps on P(Y)\mathcal P(Y)P(Y). These results do not settle Problem 624.

Formalization Note. Counting form with natural numbers (truncated subtraction is harmless since ∣Ig(Y)∣≤n|I_g(Y)|\le n∣Ig​(Y)∣≤n); UUU is an arbitrary Fintype with Fintype.card U = 2 ^ k.

Preamble
import Mathlib
import Definitions.Def_Erdos624_defs
open Finset
Formal statement
namespace Erdos624

theorem core_compression_surplus {U : Type*} [Fintype U] [DecidableEq U] (k : ℕ) (hk : 3 ≤ k)
    (hU : Fintype.card U = 2 ^ k) (S : Finset U) (hS : #S ≤ k - 2) (h g : Finset U → U)
    (hsmall : ∀ Y ∈ (powersetCard k (univ : Finset U)).filter (fun Y => S ⊆ Y),
      64 * #(Y.powerset.image h) ≤ 2 ^ k) :
    2 ^ k * #((powersetCard k (univ : Finset U)).filter (fun Y => S ⊆ Y)) ≤
      64 * ∑ Y ∈ (powersetCard k (univ : Finset U)).filter (fun Y => S ⊆ Y),
        (2 ^ k - #(Y.powerset.image h ∪ Y.powerset.image g)) := by sorry

end Erdos624
Source
Erdős Problem 624 (https://www.erdosproblems.com/624); (3) of the analysis derived from GPT 6.1 Sol's analysis (sixth report, Oct 2026), relayed by Ethan Cheung; Lean-verified by Grok Bot for Ethan Cheung (Oct 24 2026)

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