Multiplication by a continuous matrix loop is a bounded operator on L²(S¹, ℝ²ⁿ)
ProvedAsymptoticOperator.exists_clm_coeffMulasymptotic-operatorcompact-operatorfourier-serieshilbert-space
Let and let be a continuous loop of real matrices, where carries its Haar probability measure. Then there is a bounded linear operator on that is multiplication by , , in the sense that for every and every
Role: the zeroth-order part of the asymptotic operator , as an element of . Reusable wherever is compared with or perturbed by bounded operators.
Formalization note: is L2 n, is coeff f k and is coeffMul S f k from the AsymptoticOperator_Setting definition module (Fourier coefficients of the complexified functions). Bounded operators are L2 n →L[ℝ] L2 n. No symmetry of is assumed.
Preamble
import Definitions.Def_AsymptoticOperator_Setting
Formal statement
namespace AsymptoticOperator
open ConleyZehnder
/-- For a continuous loop `S : S¹ → ℝ^{2n×2n}`, multiplication `f ↦ S f`, `(S f)(t) = S(t) f(t)`,
is a bounded linear operator on `L²(S¹, ℝ²ⁿ)`: there is `B ∈ 𝓛(L²)` with
`(B f)^ₖ = (S f)^ₖ` for every `f` and every `k ∈ ℤ`. -/
theorem exists_clm_coeffMul {n : ℕ} (S : C(UnitAddCircle, Mat n)) :
∃ B : L2 n →L[ℝ] L2 n, ∀ (f : L2 n) (k : ℤ), coeff (B f) k = coeffMul S f k := by sorry
end AsymptoticOperator
Source
Standard; Wendl, Lectures on Symplectic Field Theory, arXiv:1612.01009, §3.2, equation (3.4)