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Finite seed certificate implies an asymptotic separation

Proved
SensitivityCampaign.finite_certificate

by marwahaha · Oct 15, 2026 · Mathlib 0df444a (Lean v4.33.1)

block-sensitivityboolean-functionssensitivity

Let f:{0,1}n→{0,1}f:\{0,1\}^n\to\{0,1\}f:{0,1}n→{0,1} be a total Boolean function and let xxx be any input. Suppose integers A,B>1A,B>1A,B>1 satisfy s(f)≤As(f)\le As(f)≤A and bs(f,x)≥Bbs(f,x)\ge Bbs(f,x)≥B. For every real a≥0a\ge0a≥0 with Aa≤BA^a\le BAa≤B, prove the campaign's asymptotic claim at exponent aaa: for every ε>0\varepsilon>0ε>0 and every integer S≥2S\ge2S≥2, some total Boolean function ggg satisfies s(g)≥Ss(g)\ge Ss(g)≥S and bs(g)≥s(g)a−εbs(g)\ge s(g)^{a-\varepsilon}bs(g)≥s(g)a−ε. The conclusion must include arbitrarily large sensitivity. No normalization hypothesis is imposed on fff or xxx; establishing the necessary normalization is part of the proof.

Preamble
import Mathlib
import Definitions.Def_SensitivityCampaign
open OAI.Paper320
Formal statement
theorem SensitivityCampaign.finite_certificate
    {n : ℕ} (f : (Fin n → Bool) → Bool) (x : Fin n → Bool)
    (A B : ℕ) (a : ℝ)
    (hA : 1 < A) (hB : 1 < B) (ha : 0 ≤ a)
    (hs : sensitivity f ≤ A) (hb : B ≤ blockSensitivityAt f x)
    (hpow : (A : ℝ) ^ a ≤ (B : ℝ)) :
    SensitivityCampaign.AchievesExponent a := by sorry
Source
https://github.com/bigospeedrun/site/issues/2
Read-back

What the Lean code literally says, in plain math · Codex (independent auditor sub-agent)

For a Boolean function ggg on mmm bits, let s(g)s(g)s(g) be the maximum, over all inputs, of the number of individual coordinates whose flip changes its output, and let b(g,y)b(g,y)b(g,y) be the maximum size of a family of pairwise disjoint nonempty coordinate sets whose separate flips at input yyy each change its output; the empty family is permitted and has size zero. Write b(g)b(g)b(g) for the maximum of b(g,y)b(g,y)b(g,y) over all inputs yyy. For every natural number nnn, every Boolean function fff on nnn bits, every input xxx, all natural numbers A,BA,BA,B with A>1A>1A>1 and B>1B>1B>1, and every real a≥0a≥0a≥0, if s(f)≤As(f)≤As(f)≤A, B≤b(f,x)B≤b(f,x)B≤b(f,x), and Aa≤BA^a≤BAa≤B after interpreting A,BA,BA,B as real numbers, then the following holds: For every real ε>0ε>0ε>0 and every natural number S≥2S≥2S≥2, there exist a natural number mmm and a Boolean function ggg on mmm bits such that S≤s(g)S≤s(g)S≤s(g) and s(g)a−ε≤b(g)s(g)^{a-ε}≤b(g)s(g)a−ε≤b(g), with the power taken in the reals. The witnesses may depend on both εεε and SSS, and a−εa-εa−ε may be negative; zero-dimensional witnesses are ruled out by S≤s(g)S≤s(g)S≤s(g). Although n=0n=0n=0 is allowed by its quantifier, its hypotheses cannot hold because then b(f,x)=0b(f,x)=0b(f,x)=0.

Human review
  • Endorsed by marwahaha · Oct 15, 2026

    Confirmed by the moderator at approval.

  • Endorsed by Shuze Chen · Oct 16, 2026

    Confirmed by the moderator at approval.

  • Endorsed by Leo Shaposhnik · Oct 16, 2026

    Confirmed by the mission captain (proposal self-audit).

  • Endorsed by @bwdaugherty · Oct 16, 2026

    Confirmed by the mission captain (proposal self-audit).

  • Endorsed by abhishekdpseok · Oct 16, 2026

    Confirmed by the mission captain (proposal self-audit).

  • Endorsed by Robin Kothari · Oct 16, 2026

    Confirmed by the mission captain (proposal self-audit).

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