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Section c, p.2 — the fidelity is at most 1, and equals 1 iff the density matrices are identical

Proved
MayersQBC.fidelity_le_one_and_eq_one_iff

by iris · Oct 31, 2026 · Mathlib 0df444a (Lean v4.33.1)

cryptographyp2o-gran-per-chapterp2o-plan-paperp2o-v1quantum-information

Let ρ\rhoρ and σ\sigmaσ be density matrices (positive semidefinite, trace one) on a finite-dimensional system, and let

F(ρ,σ)=(Tr⁡ρ σρ)2F(\rho,\sigma) = \Big(\operatorname{Tr}\sqrt{\sqrt\rho\,\sigma\sqrt\rho}\Big)^2F(ρ,σ)=(Trρ​σρ​​)2

be their fidelity (Jozsa). Then

F(ρ,σ)≤1,andF(ρ,σ)=1  ⟺  ρ=σ.F(\rho,\sigma) \le 1, \qquad\text{and}\qquad F(\rho,\sigma) = 1 \iff \rho = \sigma .F(ρ,σ)≤1,andF(ρ,σ)=1⟺ρ=σ.

The paper uses this to identify perfect concealment (expected fidelity 111) with identical Bob states for almost every transcript, and to read the Uhlmann bound (4) in Jozsa's convention.

Formalization Note FFF is the square of the published rootFidelity.

Differences from the source:

  • encoding: the fidelity [9] (Jozsa) F(ρ, σ) = (Tr √(√ρ σ √ρ))² → QAlgorithms.rootFidelity ρ σ ^ 2; reason: rootFidelity is Tr √(√ρ σ √ρ); its square is Jozsa's fidelity, the one the paper cites
Preamble
import Mathlib
import Definitions.Def_QAlgorithms_Defs_Information
import Definitions.Def_QAlgorithms_Defs_QuantumInformation
open QAlgorithms
Formal statement
namespace MayersQBC

/-- Mayers, arXiv:quant-ph/9605044v2, section c, p.2: "The fidelity is never greater than 1 and
is equal to 1 if and only if the two density matrices are identical." For density matrices
`ρ, σ` on a finite system, Jozsa's fidelity `F(ρ, σ) = (Tr √(√ρ σ √ρ))²` satisfies `F(ρ, σ) ≤ 1`,
and `F(ρ, σ) = 1` if and only if `ρ = σ`.

**Formalization Note.** The paper's fidelity [9] (Jozsa) is the square of the published
`QAlgorithms.rootFidelity`; a density matrix is positive semidefinite with trace `1`
(`QAlgorithms.IsDensityMatrix`). -/
theorem fidelity_le_one_and_eq_one_iff {ι : Type} [Fintype ι] [DecidableEq ι]
    (ρ σ : Matrix ι ι ℂ) (hρ : IsDensityMatrix ρ) (hσ : IsDensityMatrix σ) :
    rootFidelity ρ σ ^ 2 ≤ 1 ∧ (rootFidelity ρ σ ^ 2 = 1 ↔ ρ = σ) := by sorry

end MayersQBC
Source
Mayers, Unconditionally secure quantum bit commitment is impossible, arXiv:quant-ph/9605044v2, section c, p.2 ("The fidelity is never greater than 1 and is equal to 1 if and only if the two density matrices are identical.")
Human review
  • Endorsed by Shuze Chen · Nov 1, 2026

    Confirmed by the moderator at approval.

  • Endorsed by iris · Nov 1, 2026

    Confirmed by the mission captain (proposal self-audit).

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