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Norms of Gaussian vectors: E∥hN∥2−E∥gn∥2≥N−n\mathbb E\|h_N\|_2-\mathbb E\|g_n\|_2\ge\sqrt N-\sqrt nE∥hN​∥2​−E∥gn​∥2​≥N​−n​ for 1≤n≤N1\le n\le N1≤n≤N

Proved
GaussianMatrix.expectation_norm_gaussian_diff

by tc · Oct 9, 2026 · Mathlib 0df444a (Lean v4.33.1)

chi-distributionexpectationgamma-functiongaussian-vectorsgordons-theorem

Let 1≤n≤N1\le n\le N1≤n≤N be integers. Let hhh be a standard Gaussian vector in RN\mathbb R^NRN and ggg a standard Gaussian vector in Rn\mathbb R^nRn, each with independent N(0,1)N(0,1)N(0,1) coordinates, and let ∥⋅∥2\|\cdot\|_2∥⋅∥2​ be the Euclidean norm. Then

N−n  ≤  E ∥h∥2−E ∥g∥2.\sqrt N-\sqrt n\;\le\;\mathbb E\,\|h\|_2-\mathbb E\,\|g\|_2 .N​−n​≤E∥h∥2​−E∥g∥2​.

Equivalently, m↦E∥gm∥2−mm\mapsto \mathbb E\|g_m\|_2-\sqrt mm↦E∥gm​∥2​−m​ is nondecreasing on m≥1m\ge1m≥1, where gmg_mgm​ is standard Gaussian in Rm\mathbb R^mRm.

This is the elementary input that turns Gordon's bound E σmin⁡(G)≥E∥hN∥2−E∥gn∥2\mathbb E\,\sigma_{\min}(G)\ge\mathbb E\|h_N\|_2-\mathbb E\|g_n\|_2Eσmin​(G)≥E∥hN​∥2​−E∥gn​∥2​ into the familiar E σmin⁡(G)≥N−n\mathbb E\,\sigma_{\min}(G)\ge\sqrt N-\sqrt nEσmin​(G)≥N​−n​. Note that E∥hN∥2≤N\mathbb E\|h_N\|_2\le\sqrt NE∥hN​∥2​≤N​, so the inequality is not a consequence of Jensen's inequality. It is sharp to second order: with am=E∥gm∥2a_m=\mathbb E\|g_m\|_2am​=E∥gm​∥2​, the gap (am+1−am)−(m+1−m)(a_{m+1}-a_m)-(\sqrt{m+1}-\sqrt m)(am+1​−am​)−(m+1​−m​) is of order m−3/2/8m^{-3/2}/8m−3/2/8. One proof uses am=2 Γ(m+12)/Γ(m2)a_m=\sqrt2\,\Gamma(\tfrac{m+1}2)/\Gamma(\tfrac m2)am​=2​Γ(2m+1​)/Γ(2m​), hence amam+1=ma_m a_{m+1}=mam​am+1​=m, together with log-convexity of Γ\GammaΓ and a monotone-ratio argument that yields am2≤m−12+320ma_m^2\le m-\tfrac12+\tfrac{3}{20m}am2​≤m−21​+20m3​.

Formalization Note. The law of hhh is Measure.pi fun _ : Fin N => gaussianReal 0 1, and ∥x∥2\|x\|_2∥x∥2​ is written ∑ixi2\sqrt{\sum_i x_i^2}∑i​xi2​​. The hypothesis n≥1n\ge1n≥1 is necessary: for n=0n=0n=0 the claim would read N≤E∥hN∥2\sqrt N\le\mathbb E\|h_N\|_2N​≤E∥hN​∥2​, which is false for every N≥1N\ge1N≥1 (e.g. E∥h1∥=2/π<1\mathbb E\|h_1\|=\sqrt{2/\pi}<1E∥h1​∥=2/π​<1). The hypothesis n≤Nn\le Nn≤N is also needed, since the inequality reverses for N<nN<nN<n. Both integrands are integrable.

Preamble
import Definitions.Def_GaussianMatrix_basic

open MeasureTheory ProbabilityTheory
open scoped Matrix
Formal statement
namespace GaussianMatrix

theorem expectation_norm_gaussian_diff {N n : ℕ} (hn : 1 ≤ n) (hnN : n ≤ N) :
    Real.sqrt N - Real.sqrt n ≤
      ∫ x, Real.sqrt (∑ i, x i ^ 2) ∂(Measure.pi fun _ : Fin N => gaussianReal 0 1)
        - ∫ x, Real.sqrt (∑ i, x i ^ 2) ∂(Measure.pi fun _ : Fin n => gaussianReal 0 1) := by sorry

end GaussianMatrix
Source
R. Vershynin, High-Dimensional Probability (Cambridge Univ. Press, 2018), hint to Exercise 7.3.4 (p. 170): 'f(n) := E||g||_2 - sqrt(n) is increasing in dimension n (take this fact for granted; it can be proved by a tedious calculation)'. Used in K. R. Davidson and S. J. Szarek, 'Local operator theory, random matrices and Banach spaces', Handbook of the Geometry of Banach Spaces I (2001), proof of Theorem II.13 (theorem number from memory).

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