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Deficit two: the union of two skew omitted circuits is an actual minimal witness (Erdős 624)

Proved
Erdos624.skew_omitted_union_witness

by Ethan Cheung Wang · Oct 25, 2026 · Mathlib 0df444a (Lean v4.33.1)

combinatoricserdos-problems

Setting: UUU is a finite set of inputs, L:P(U)→P(C)L:\mathcal P(U)\to\mathcal P(C)L:P(U)→P(C) an arbitrary list map (the actual colour lists), kkk a natural number. A colour uuu is nonbottom if u∉L(∅)u\notin L(\varnothing)u∈/L(∅) and covering if every kkk-subset Y⊆UY\subseteq UY⊆U contains some AAA with u∈L(A)u\in L(A)u∈L(A). An actual minimal witness of uuu is F⊆UF\subseteq UF⊆U with u∈L(F)u\in L(F)u∈L(F) and u∉L(F′)u\notin L(F')u∈/L(F′) for every F′⊊FF'\subsetneq FF′⊊F. A valid label for uuu is a map p:U→Vp:U\to Vp:U→V into an F2\mathbb F_2F2​-vector space with ∑x∈Fp(x)=0\sum_{x\in F}p(x)=0∑x∈F​p(x)=0 for every actual minimal witness FFF with 1≤∣F∣≤k1\le|F|\le k1≤∣F∣≤k. For T⊆UT\subseteq UT⊆U, rk⁡(T)=dim⁡span⁡p(T)\operatorname{rk}(T)=\dim\operatorname{span}p(T)rk(T)=dimspanp(T) and rk⁡(U)=dim⁡span⁡p(U)\operatorname{rk}(U)=\dim\operatorname{span}p(U)rk(U)=dimspanp(U) (the dimension of the valid parity space). Theorem. Let uuu be nonbottom and covering with valid label ppp of global rank ≥k−2\ge k-2≥k−2 (stated as k≤rk⁡(U)+2k\le\operatorname{rk}(U)+2k≤rk(U)+2). Let A,B⊆UA,B\subseteq UA,B⊆U be disjoint, nonempty, with ∑Ap=∑Bp=0\sum_Ap=\sum_Bp=0∑A​p=∑B​p=0, such that the only zero-sum subsets of A∪BA\cup BA∪B are ∅,A,B,A∪B\varnothing,A,B,A\cup B∅,A,B,A∪B, and with u∉L(A)u\notin L(A)u∈/L(A), u∉L(B)u\notin L(B)u∈/L(B), ∣A∪B∣≤k|A\cup B|\le k∣A∪B∣≤k. Then A∪BA\cup BA∪B is an actual minimal witness of uuu: u∈L(A∪B)u\in L(A\cup B)u∈L(A∪B) and u∉L(F′)u\notin L(F')u∈/L(F′) for all F′⊊A∪BF'\subsetneq A\cup BF′⊊A∪B.

Source: converse half of the deficit-two classification in 'Actual Witness Spans and Intrinsic Kernel Diversity'. Note: the source derives ∣A∪B∣≤k|A\cup B|\le k∣A∪B∣≤k from exact global rank k−2k-2k−2; here it is an explicit hypothesis, and 'genuine hole' is weakened to u∉L(A)u\notin L(A)u∈/L(A), u∉L(B)u\notin L(B)u∈/L(B).

Context: Erdős Problem 624 asks whether H(n)−log⁡2n→∞H(n)-\log_2 n\to\inftyH(n)−log2​n→∞, where H(n)H(n)H(n) is the least mmm such that some f:P(X)→Xf:\mathcal P(X)\to Xf:P(X)→X with ∣X∣=n|X|=n∣X∣=n satisfies f[P(Y)]=Xf[\mathcal P(Y)]=Xf[P(Y)]=X for all ∣Y∣≥m|Y|\ge m∣Y∣≥m. This is an auxiliary finite statement from Sol's Round 13 notes on the two-track (PAIR) case. It does not settle Erdős Problem 624, PAIR or Step 17; the initial near-critical population those notes start from is not established.

Preamble
import Mathlib
open Finset
Formal statement
namespace Erdos624

theorem skew_omitted_union_witness {U : Type*} [Fintype U] [DecidableEq U] {C : Type*} [DecidableEq C]
    {W : Type*} [AddCommGroup W] [Module (ZMod 2) W]
    (L : Finset U → Finset C) (k : ℕ) (u : C) (hu : u ∉ L ∅)
    (hcov : ∀ Y : Finset U, #Y = k → ∃ A ⊆ Y, u ∈ L A)
    (p : U → W)
    (hvalid : ∀ F : Finset U, 0 < #F → #F ≤ k → u ∈ L F → (∀ F' ⊂ F, u ∉ L F') →
      ∑ x ∈ F, p x = 0)
    (hglob : k ≤ Module.finrank (ZMod 2) (Submodule.span (ZMod 2) (Set.range p)) + 2)
    (A B : Finset U) (hAB : Disjoint A B) (hA : A.Nonempty) (hB : B.Nonempty)
    (hA0 : ∑ x ∈ A, p x = 0) (hB0 : ∑ x ∈ B, p x = 0)
    (hzs : ∀ G ⊆ A ∪ B, ∑ x ∈ G, p x = 0 → G = ∅ ∨ G = A ∨ G = B ∨ G = A ∪ B)
    (huA : u ∉ L A) (huB : u ∉ L B) (hk : #(A ∪ B) ≤ k) :
    u ∈ L (A ∪ B) ∧ ∀ F' ⊂ A ∪ B, u ∉ L F' := by sorry

end Erdos624
Source
Erdős Problem 624 (https://www.erdosproblems.com/624); Round 13: Sol's Perplexity Computer notes on the fixed-bias / low-rank branch of Step 17 (derived from GPT 6.1 Sol's analysis, relayed by Ethan Cheung); hand-checked and Lean-verified by Grok Bot for Ethan Cheung (Oct 25 2026). Auxiliary result only; does NOT settle PAIR / Step 17 / #624.

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