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Continuity equation: integral form   ⟺  \iff⟺ differential form

Proved
ContinuityEqWiki.integral_form_iff_differential_form

by Lucas · Oct 9, 2026 · Mathlib 0df444a (Lean v4.33.1)

continuity-equationmathematical-physics

Let ρ:R×R3→R\rho:\mathbb R\times\mathbb R^3\to\mathbb Rρ:R×R3→R be the volume density of a quantity qqq, j:R×R3→R3\mathbf j:\mathbb R\times\mathbb R^3\to\mathbb R^3j:R×R3→R3 its flux, and σ:R×R3→R\sigma:\mathbb R\times\mathbb R^3\to\mathbb Rσ:R×R3→R its generation rate per unit volume per unit time. Assume ρ\rhoρ and j\mathbf jj are C1C^1C1 jointly in (t,x)(t,x)(t,x) and σ\sigmaσ is continuous. Then the following are equivalent.

  1. Integral form. For every box V=∏i[ai,bi]V=\prod_i[a_i,b_i]V=∏i​[ai​,bi​] with ai<bia_i<b_iai​<bi​ and every time ttt,
dqdt+∮∂Vj⋅dS=Σ,q(t)=∫Vρ(t,x) dx,Σ(t)=∫Vσ(t,x) dx.\frac{dq}{dt}+\oint_{\partial V}\mathbf j\cdot d\mathbf S=\Sigma,\qquad q(t)=\int_V\rho(t,x)\,dx,\quad \Sigma(t)=\int_V\sigma(t,x)\,dx .dtdq​+∮∂V​j⋅dS=Σ,q(t)=∫V​ρ(t,x)dx,Σ(t)=∫V​σ(t,x)dx.
  1. Differential form. For every ttt and xxx,
∂ρ∂t+∇⋅j=σ.\frac{\partial\rho}{\partial t}+\nabla\cdot\mathbf j=\sigma .∂t∂ρ​+∇⋅j=σ.

This is the central statement of the source: any continuity equation can be expressed either in integral form, for finite regions, or in differential form, at points.

Formalization Note The source quantifies over all closed surfaces SSS enclosing a volume VVV. Here VVV ranges over non-degenerate axis-parallel boxes, the setting of Mathlib's divergence theorem. This weakens the hypothesis of the direction (1)⇒\Rightarrow⇒(2) and the conclusion of (2)⇒\Rightarrow⇒(1).

Preamble
import Mathlib
import Definitions.Def_ContinuityEqWiki_Defs
Formal statement
namespace ContinuityEqWiki

theorem integral_form_iff_differential_form
    (ρ : ℝ → Space → ℝ) (j : ℝ → Space → Space) (σ : ℝ → Space → ℝ)
    (hρ : ContDiff ℝ 1 (Function.uncurry ρ)) (hj : ContDiff ℝ 1 (Function.uncurry j))
    (hσ : Continuous (Function.uncurry σ)) :
    IntegralForm ρ j σ ↔ DifferentialForm ρ j σ := by sorry

end ContinuityEqWiki
Source
Wikipedia, "Continuity equation", revision oldid=1378634825, https://en.wikipedia.org/w/index.php?title=Continuity_equation&oldid=1378634825, section "General equation", subsections "Integral form" and "Differential form"
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What the Lean code literally says, in plain math · Aristotle (Harmonic) - drafting agent, non-blind read-back

Non-blind read-back — not independent testimony. This read-back was written by the same agent (Aristotle, by Harmonic) that drafted the Lean statement it describes, at the explicit request of the proposal owner. Its author knew the source text and the intended meaning while writing it, so it must not be mistaken for a blind, independent audit. Reviewers should compare the Lean code against the source themselves.

Let ρ,σ:R×R3→R\rho,\sigma:\mathbb R\times\mathbb R^3\to\mathbb Rρ,σ:R×R3→R and j:R×R3→R3\mathbf j:\mathbb R\times\mathbb R^3\to\mathbb R^3j:R×R3→R3 (written f(t,x)f(t,x)f(t,x)). Assume (t,x)↦ρ(t,x)(t,x)\mapsto\rho(t,x)(t,x)↦ρ(t,x) and (t,x)↦j(t,x)(t,x)\mapsto\mathbf j(t,x)(t,x)↦j(t,x) are C1C^1C1 on R×R3\mathbb R\times\mathbb R^3R×R3 and (t,x)↦σ(t,x)(t,x)\mapsto\sigma(t,x)(t,x)↦σ(t,x) is continuous. The statement is the equivalence of:

  1. for all a,b∈R3a,b\in\mathbb R^3a,b∈R3 with ai<bia_i<b_iai​<bi​ for i=0,1,2i=0,1,2i=0,1,2, and all t∈Rt\in\mathbb Rt∈R,
dds∣s=t∫[a,b]ρ(s,x) dx+∑i=02(∫[a′,b′]j(t,ιi(bi,y))i dy−∫[a′,b′]j(t,ιi(ai,y))i dy)=∫[a,b]σ(t,x) dx,\frac{d}{ds}\Big|_{s=t}\int_{[a,b]}\rho(s,x)\,dx+\sum_{i=0}^{2}\left(\int_{[a',b']}\mathbf j(t,\iota_i(b_i,y))_i\,dy-\int_{[a',b']}\mathbf j(t,\iota_i(a_i,y))_i\,dy\right)=\int_{[a,b]}\sigma(t,x)\,dx,dsd​​s=t​∫[a,b]​ρ(s,x)dx+i=0∑2​(∫[a′,b′]​j(t,ιi​(bi​,y))i​dy−∫[a′,b′]​j(t,ιi​(ai​,y))i​dy)=∫[a,b]​σ(t,x)dx,

where a′,b′∈R2a',b'\in\mathbb R^2a′,b′∈R2 are a,ba,ba,b with coordinate iii deleted and ιi(s,y)\iota_i(s,y)ιi​(s,y) inserts sss as coordinate iii into y∈R2y\in\mathbb R^2y∈R2 (the derivative is the one-variable derivative, junk 000 if it did not exist); 2. for all t∈Rt\in\mathbb Rt∈R and x∈R3x\in\mathbb R^3x∈R3,

∂tρ(t,x)+∑i=02∂i(j(t,⋅)i)(x)=σ(t,x).\partial_t\rho(t,x)+\sum_{i=0}^{2}\partial_i\big(\mathbf j(t,\cdot)_i\big)(x)=\sigma(t,x).∂t​ρ(t,x)+i=0∑2​∂i​(j(t,⋅)i​)(x)=σ(t,x).

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