Corollary 10: exponential trace inequality resolving the Ruskai question
OpenQAlgorithms.Papers.Independent.Intakethird100.P52.exponential_trace_boundAll Hilbert spaces below are finite dimensional and nonzero over . A density operator is positive semidefinite with trace one. Every spectral power is zero on the kernel, including zero and negative powers. Information quantities use base-two logarithms, with ; the operator logarithms in exponential formulas are natural logarithms.
Let be a density operator, let be arbitrary, and let be a strict CPTP map. Then
Here the exponential is the ordinary exponential of a Hermitian operator and satisfies .
This gives the exponential trace inequality posed by Ruskai.
import Definitions.Def_QAlgorithms_Papers_Independent_Intakethird100_P52
noncomputable section
open scoped Matrix ComplexOrder
namespace QAlgorithms.Papers.Independent.Intakethird100.P52
attribute [local instance] Classical.propDecidable Classical.decEq
open QAlgorithms.Papers.Independent.Information100.P63 (Mat)
open QAlgorithms.Papers.Independent.Dependency50.P21 (channelAdjoint petz marginalAB)
open QAlgorithms.Papers.Independent.Dependency50.P35 (tr elog maxRelative)
open QAlgorithms.Papers.Independent.Information100.P71 (supportPower)
open QAlgorithms.Papers.Independent.Renew46.P35 (HasMarkovBlocks)
/-- Corollary 10, PDF p.13, equation (3.50). Natural logarithms and ordinary
exponential of the Hermitian exponent; exp(0)=I even on its zero eigenspace. -/
theorem exponential_trace_bound {H K : Type} [Fintype H] [Fintype K]
[DecidableEq H] [DecidableEq K] [Nonempty H] [Nonempty K]
(rho sigma : Mat H) (hrho : IsDensityMatrix rho)
(hrhoPD : rho.PosDef) (hsigmaPD : sigma.PosDef)
(N : Superop H K) (hN : IsStrictChannel N) :
tr (cfc Real.exp (cfc Real.log sigma +
channelAdjoint N (cfc Real.log (N rho) - cfc Real.log (N sigma)))) ≤ 1 := by sorry
end QAlgorithms.Papers.Independent.Intakethird100.P52
end
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What the Lean code literally says, in plain math · gpt-6.1-sol
For finite nonempty types , each with decidable equality, let be complex matrices on , assume that is positive semidefinite with trace and is positive definite, and assume that is positive definite without requiring trace . Let admit a finite Kraus representation with , and assume additionally that is positive definite whenever is positive definite. With , the assertion is
where and mean continuous functional calculus for the real natural logarithm and real exponential, respectively.
Confirmed by the mission captain (proposal self-audit).
Confirmed by the moderator at approval.