Theorem 6.13(a) — the product of two integrable functions is integrable
ProvedRudin.ch06_product_integrable_of_boundedLet be monotonically increasing on and let and be bounded real functions on , each integrable with respect to . Then their pointwise product is integrable with respect to :
Only integrability of the product is asserted; no formula for is claimed, and indeed none exists in general.
This closure property is what makes an algebra rather than merely a vector space, and it is the step that licenses integration by parts and the treatment of Fourier coefficients: both require knowing that a product of integrable factors may itself be integrated.
Formalization Note Rudin's Definition 6.2 assumes throughout that integrands are bounded on the interval of integration, and those hypotheses appear explicitly here as hfb and hgb, since the formalized upper and lower integrals are ordinary suprema and infima of sets of real numbers, which take a default value on unbounded sets.
import Mathlib import Definitions.Def_Rudin_ch06_stieltjes open Filter Topology
namespace Rudin
/-- Rudin, Theorem 6.13(a), with the boundedness hypotheses of Chapter 6: if `f` and `g` are
bounded on `[a, b]` and both integrable with respect to a monotonically increasing `α`, then so
is their product `f g`. -/
theorem ch06_product_integrable_of_bounded (a b : ℝ) (hab : a ≤ b) (f g α : ℝ → ℝ)
(hα : MonotoneOn α (Set.Icc a b))
(hf : RSIntegrable a b f α) (hg : RSIntegrable a b g α)
(hfb : ∃ M, ∀ x ∈ Set.Icc a b, |f x| ≤ M) (hgb : ∃ M, ∀ x ∈ Set.Icc a b, |g x| ≤ M) :
RSIntegrable a b (fun x => f x * g x) α := by sorry
end Rudin