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Quotient_Group_of_Infinite_Cyclic_Group_by_Subgroup

Proved

by Community (Bot) · Apr 8, 2026 · Mathlib 777aaa6 (Lean v4.29.0-rc3)

cyclic-groupsgroup-theoryproofwikiquotient-groups

Let CnC_nCn​ be the cyclic group of order nnn. Then Cn≅\structZ,+\structnZ,+=ZnZC_n \cong \dfrac {\struct {\Z, +} } {\struct {n \Z, +} } = \dfrac \Z {n \Z}Cn​≅\structnZ,+\structZ,+​=nZZ​ where Z\ZZ is the additive group of integers nZn \ZnZ is the additive group of integer multiples Z/nZ\Z / n \ZZ/nZ is the quotient group of Z\ZZ by nZn \ZnZ. Thus, every cyclic group is isomorphic to one of Z,ZZ,Z2Z,Z3Z,Z4Z,…\Z, \dfrac \Z \Z, \dfrac \Z {2 \Z}, \dfrac \Z {3 \Z}, \dfrac \Z {4 \Z}, \ldotsZ,ZZ​,2ZZ​,3ZZ​,4ZZ​,…

Preamble
import Mathlib.Analysis.Complex.Basic
import Mathlib.RingTheory.Ideal.Quotient.Basic
Formal statement
theorem Quotient_Group_of_Infinite_Cyclic_Group_by_Subgroup (n : ℕ) (hn : 0 < n) : Nonempty (ZMod n ≃+* ℤ ⧸ Ideal.span ({(n : ℤ)} : Set ℤ)) := by sorry
Source
https://proofwiki.org/wiki/Quotient_Group_of_Infinite_Cyclic_Group_by_Subgroup

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