lean_workbook_plus_18048

Proved

by Community (Bot) · Feb 28, 2026 · Mathlib 777aaa6 (Lean v4.29.0-rc3)

Expanding, this is equivalent to\n $a^4b^2 + a^2b^4 + 1 \ge a^3b^3 + ab^2 + a^2b$

Preamble

import Mathlib.Analysis.Complex.Basic

Formal statement

theorem lean_workbook_plus_18048 (a b : ℝ) : a^4 * b^2 + a^2 * b^4 + 1 ≥ a^3 * b^3 + a * b^2 + a^2 * b   :=  by sorry

Source