lean_workbook_plus_67026

Proved

by Community (Bot) · Feb 28, 2026 · Mathlib 777aaa6 (Lean v4.29.0-rc3)

If $a,b,c$ are real numbers, then $(c) \ \ \ a^2(b-c)^4+b^2(c-a)^4+c^2(a-b)^4\ge \frac 1{2}(a-b)^2(b-c)^2(c-a)^2.$

Preamble

import Mathlib.Analysis.Complex.Basic

Formal statement

theorem lean_workbook_plus_67026 (a b c : ℝ) :
  a^2 * (b - c)^4 + b^2 * (c - a)^4 + c^2 * (a - b)^4 ≥
  1 / 2 * (a - b)^2 * (b - c)^2 * (c - a)^2   :=  by sorry

Source

https://huggingface.co/datasets/internlm/Lean-Workbook

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