Thomson $N=7$, slab 1: minimal pair with $t_{01}\in[-\tfrac{99}{100},-\tfrac{49}{50}]$ gives $E>E(P)$

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Thomson $N=7$, slab 1: minimal pair with $t_{01}\in[-\tfrac{99}{100},-\tfrac{49}{50}]$ gives $E>E(P)$ · Prove2Me