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D4.4a: swapped-S cycle renewal

Proved
FiniteMagmaE677.period_four_swapped_s_gives_cycle_renewal

by mysticflounder · Sep 24, 2026 · Mathlib 0df444a (Lean v4.33.1)

e677magmaperiod-fourrenewal

Write Lx(y)=x⋄yL_x(y)=x\diamond yLx​(y)=x⋄y and let Cz={Lxi(z):0≤i<dz}C_z=\{L_x^i(z):0\le i<d_z\}Cz​={Lxi​(z):0≤i<dz​} for an exact first-return cycle of length dzd_zdz​. Let a finite magma satisfy E677. Assume the published distinguished period-four packet and S-tagged start at x,c1,c2,c3x,c_1,c_2,c_3x,c1​,c2​,c3​. Put q=c2⋄xq=c_2\diamond xq=c2​⋄x, s=c3⋄qs=c_3\diamond qs=c3​⋄q and t=c2⋄st=c_2\diamond st=c2​⋄s. Suppose Lx(q)=sL_x(q)=sLx​(q)=s, Lx(s)=qL_x(s)=qLx​(s)=q, ttt is outside {x,c1,c2,c3,q,s}\{x,c_1,c_2,c_3,q,s\}{x,c1​,c2​,c3​,q,s}, the trace at ttt is initialized at depth zero with exact first-return data, and t⋄c2=c3t\diamond c_2=c_3t⋄c2​=c3​.

Then these inputs extend to a cycle-renewal packet. In particular, (t⋄c3)⋄t=c1(t\diamond c_3)\diamond t=c_1(t⋄c3​)⋄t=c1​, q⋄c2=s⋄c2q\diamond c_2=s\diamond c_2q⋄c2​=s⋄c2​, and p=q⋄(q⋄x)p=q\diamond(q\diamond x)p=q⋄(q⋄x) is fresh outside the same six points and satisfies p⋄q=qp\diamond q=qp⋄q=q. The packet retains the full three-way classification of t⋄c3t\diamond c_3t⋄c3​: the dual-collision case, contact at a strictly positive phase of CtC_tCt​, or a fresh cycle disjoint from CtC_tCt​, with the associated equations and exact first-return data.

Preamble
import Definitions.Def_FiniteMagmaE677_sswap_renewal
import Mathlib

universe u
open FiniteMagmaE677
Formal statement
theorem FiniteMagmaE677.period_four_swapped_s_gives_cycle_renewal
{α : Type u} [Fintype α] (op : α → α → α) (h : FiniteMagmaE677.E677 op)
(x c1 c2 c3 : α)
(packet : FirstReturn.D4Distinguished op x c1 c2 c3)
(start : FirstReturn.STaggedStart op x c1 c2 c3)
(q_to_s : op x (op c2 x) = op c3 (op c2 x))
(s_to_q : op x (op c3 (op c2 x)) = op c2 x)
(fresh : FirstReturn.FreshOutsideSix x c1 c2 c3
  (op c2 x) (op c3 (op c2 x)) (op c2 (op c3 (op c2 x))))
(initial_trace : FirstReturn.D4Trace op x c1 c2 c3 (op c2 (op c3 (op c2 x))) 0)
(first : FirstReturn.D4FirstReturn op x c1 c2 c3 (op c2 (op c3 (op c2 x))) 0)
(bridge : op (op c2 (op c3 (op c2 x))) c2 = c3) :
SSwap.CycleRenewal op x c1 c2 c3 (op c2 x) (op c3 (op c2 x))
  (op c2 (op c3 (op c2 x))) first := by sorry
Source
Adam McKenna, The Missing Pair (private repository), revision f9945b937be61f4ca48eb6cafdcfa07ba7a7f78c, lean/E677/Spine/Piece1D4SSwapCommonRenewal.lean, line 144. The accepted proof on this platform is the public record.

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