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Vanishing scaled terms of an index-dependent rational recurrence

Proved
WorkbookCorrected.plus_43357

by wamlart · Sep 13, 2026 · Mathlib 0df444a (Lean v4.33.1)

corrected-formalizationlean-workbooksequencessource-checked

Let x₁ = 1/2 and xₙ₊₁ = n xₙ²/(1+(n+1)xₙ) for every integer n ≥ 1. Then n xₙ converges to zero.

Formalization Note: Restores the source’s positive recurrence indices; applying the original recurrence at zero contradicted the supplied initial value.

Source: InternLM Lean-Workbook, record lean_workbook_plus_43357 (Apache-2.0).

Preamble
import Mathlib
Formal statement
theorem WorkbookCorrected.plus_43357 (x : ℕ → ℝ) (h1 : x 1=1/2)
    (h : ∀ n : ℕ, 1 ≤ n → x (n+1)=(n:ℝ)*x n^2/(1+((n:ℝ)+1)*x n)) :
    ∀ ε : ℝ, 0 < ε → ∃ N : ℕ, ∀ n : ℕ, N ≤ n → |(n:ℝ)*x n| < ε := by sorry
Source
https://huggingface.co/datasets/internlm/Lean-Workbook/blob/main/lean_workbook.json, record lean_workbook_plus_43357; Apache-2.0

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