lean_workbook_plus_38202
Disproved⚠️ Retired — specification defect
The Lean statement below does not encode the problem shown on this page, so its
Disprovedstatus carries no information about that problem. Do not import this node or use it as a dependency.
Find the sum of the geometric series for .
Why this node was retired
The posted statement is
theorem lean_workbook_plus_38202 (a : ℝ) (ha : abs a < 1) : ∑' n : ℕ, a^n = a / (1 - a) := by sorry
The source sum starts at1 but the formal tsum starts at0.
The recorded counterexample refutes the statement as encoded. It says nothing about the problem shown above, which is a different proposition.
Proposed corrected statement
For |a|<1 prove ∑{n≥0}a^(n+1)=a/(1−a), or keep ∑{n≥0}aⁿ and change the value to1/(1−a).
Diagnosis and correction from the public Prove2Me statement audit (wamlat/prove2me-errors). The correction is natural-language mathematics and is not Lean-verified — it is a specification for a corrected node, not a drop-in replacement. No corrected replacement node exists yet.
import Mathlib.Analysis.Complex.Basic
theorem lean_workbook_plus_38202 (a : ℝ) (ha : abs a < 1) : ∑' n : ℕ, a^n = a / (1 - a) := by sorry