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Appendix A, p. 966 — I+∑j=1n−1(Pj−Π)I + \sum_{j=1}^{n-1}(P^j - \Pi)I+∑j=1n−1​(Pj−Π) is Cesàro-summable to the fundamental matrix ZZZ

Proved
JewellMRP.InfiniteStep.fundamental_matrix_cesaro

by mikedeng1 · Sep 28, 2026 · Mathlib 0df444a (Lean v4.33.1)

cesaro-meanfundamental-matrixmarkov-chainp2o-batch-p200bp2o-gran-per-chapterp2o-plan-paperp2o-v1

Let PPP be an irreducible row-stochastic matrix on a nonempty finite state set, π\piπ its stationary probability vector, Π\PiΠ the matrix all of whose rows equal π\piπ, and Z=(I−P+Π)−1Z = (I - P + \Pi)^{-1}Z=(I−P+Π)−1. Put

A(n)=I+∑j=1n−1(Pj−Π),n≥1.A(n) = I + \sum_{j=1}^{n-1}\bigl(P^j - \Pi\bigr), \qquad n \ge 1 .A(n)=I+j=1∑n−1​(Pj−Π),n≥1.

Then the Cesàro means of A(n)A(n)A(n) converge to ZZZ:

lim⁡n→∞1n∑m=1nA(m)=Z.\lim_{n\to\infty}\frac1n\sum_{m=1}^{n} A(m) = Z .n→∞lim​n1​m=1∑n​A(m)=Z.

This identifies the fundamental matrix of Kemeny and Snell as the (Cesàro) sum of the deviations of the powers of PPP from their limit, which is how ZZZ enters the limiting bias.

Formalization Note The paper says the sequence "converges or is Cesàro-summable"; for periodic chains only the Cesàro limit exists, and that is what is stated. A(1)=IA(1) = IA(1)=I (empty sum).

Preamble
import Mathlib
import Definitions.Def_JewellMRP_InfiniteStep_Model

open Matrix Filter Topology
Formal statement
namespace JewellMRP.InfiniteStep

theorem fundamental_matrix_cesaro {S : Type*} [Fintype S] [DecidableEq S] [Nonempty S]
    (P : Matrix S S ℝ) (hP : IsErgodic P) (π : S → ℝ) (hπ : IsStationary P π) :
    Tendsto (cesaroMean (fun n : ℕ => 1 + ∑ j ∈ Finset.Ico 1 n, (P ^ j - limitMatrix π)))
      atTop (𝓝 (fundamentalMatrix P π)) := by sorry

end JewellMRP.InfiniteStep
Source
Jewell, Markov-Renewal Programming. II: Infinite Return Models, Example, Oper. Res. 11 (1963), p. 966, Appendix A (before Eq. (A 4))
Human review
  • Endorsed by Shuze Chen · Oct 1, 2026

    Confirmed by the moderator at approval.

  • Endorsed by mikedeng1 · Oct 1, 2026

    Confirmed by the mission captain (proposal self-audit).

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