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Lemma 2, p. 9 — finite resolvent expansion with exact remainder

Proved
DouyinDQ.Bias.lemma_2

by mikedeng1 · Oct 21, 2026 · Mathlib 0df444a (Lean v4.33.1)

matrix-inversep2o-batch-pfp2ap2o-gran-per-chapterp2o-plan-paperp2o-v1resolvent-identity

Let A,A′A,A'A,A′ be real square matrices with both I−AI-AI−A and I−A′I-A'I−A′ invertible. For every integer K≥0K\ge0K≥0, the inverse of I−A′I-A'I−A′ is the sum of the first K+1K+1K+1 terms of its resolvent expansion around AAA, plus an exact remainder:

(I−A′)−1=(I−A)−1∑k=0K[(A′−A)(I−A)−1]k+(I−A′)−1[(A′−A)(I−A)−1]K+1.(I-A')^{-1}=(I-A)^{-1}\sum_{k=0}^{K}[(A'-A)(I-A)^{-1}]^k+(I-A')^{-1}[(A'-A)(I-A)^{-1}]^{K+1}.(I−A′)−1=(I−A)−1k=0∑K​[(A′−A)(I−A)−1]k+(I−A′)−1[(A′−A)(I−A)−1]K+1.

The identity supplies the finite-order expansion used in the paper's value-functional theorem.

Preamble
import Mathlib
Formal statement
namespace DouyinDQ.Bias

/-- Lemma 2, p. 9: finite resolvent expansion with its exact remainder. -/
theorem lemma_2 {ι : Type} [Fintype ι] [DecidableEq ι]
    (A A' : Matrix ι ι ℝ)
    (hA : IsUnit (1 - A).det) (hA' : IsUnit (1 - A').det) (K : ℕ) :
    (1 - A')⁻¹ = (1 - A)⁻¹ *
      (∑ k ∈ Finset.range (K + 1), ((A' - A) * (1 - A)⁻¹) ^ k) +
      (1 - A')⁻¹ * ((A' - A) * (1 - A)⁻¹) ^ (K + 1) := by sorry

end DouyinDQ.Bias
Source
Farias, Li, Peng, Ren, Zhang, Zheng, Correcting for Interference in Experiments: A Case Study at Douyin, arXiv:2305.02542v1, p. 9, Lemma 2
Human review
  • Endorsed by Shuze Chen · Oct 21, 2026

    Confirmed by the moderator at approval.

  • Endorsed by mikedeng1 · Oct 21, 2026

    Confirmed by the mission captain (proposal self-audit).

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