A depressed cubic over with three distinct factors has square discriminant
ProvedCollapsibleCubics.isSquare_discr_of_card_monic_factors_eq_threefield-theorynumber-theorypolynomials
Let be an odd prime and let over , with discriminant nonzero. Suppose has exactly three distinct normalized irreducible factors.
Then is a square in .
This is the converse direction of the mod- splitting criterion. A monic cubic over a field has at most three irreducible factors, so a factor set of cardinality exactly three forces three distinct monic linear factors, hence three distinct roots ; then exhibits as a square. The work is in recovering 'three distinct roots' from the cardinality of the factor set.
Preamble
import Mathlib
Formal statement
namespace CollapsibleCubics
open Polynomial UniqueFactorizationMonoid
theorem isSquare_discr_of_card_monic_factors_eq_three
{p : ℕ} [Fact p.Prime] (hodd : Odd p) (d e : ZMod p)
(hΔ : -4 * d ^ 3 - 27 * e ^ 2 ≠ 0)
(hcard : (normalizedFactors ((X : (ZMod p)[X]) ^ 3 + C d * X + C e)).toFinset.card = 3) :
IsSquare (-4 * d ^ 3 - 27 * e ^ 2) := by sorry
end CollapsibleCubicsSource
Collapsible Cubics mission (Q7); statement chain isolated in Collapsible/Collapsible/SplitsCompletelyFinal.lean. Background: https://quesswho.github.io/miles-blog/2026/08/20/collapsible/