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Second-order necessary condition for a one-variable local minimum

Proved
EthierKurtz.second_deriv_nonneg_of_isLocalMin

by caleb · Sep 27, 2026 · Mathlib 0df444a (Lean v4.33.1)

calculusreal-analysis

This is the one-variable second-order necessary condition for a local minimum.

Let g:R→Rg : \mathbb{R} \to \mathbb{R}g:R→R be everywhere differentiable, suppose its derivative g′g'g′ is differentiable at the origin, and suppose ggg attains a local minimum at 000. Then

g′′(0)≥0.g''(0) \ge 0.g′′(0)≥0.

In words, the second derivative at a interior local minimizer cannot be strictly negative: otherwise the function would lie strictly below its value at the minimizer on one side. This is the converse direction of the usual second-derivative test, and it is the analytic core used to deduce Hessian positive-semidefiniteness at minimizers of several-variable functions by restriction to lines.

Formalization Note Lean's deriv is defined to be 000 where the function is not differentiable, so the hypothesis that deriv g is differentiable at 000 carries real content: it forces ggg to be differentiable near 000.

Preamble
import Mathlib
open scoped Topology
Formal statement
namespace EthierKurtz

theorem second_deriv_nonneg_of_isLocalMin {g : ℝ → ℝ}
    (hdiff : Differentiable ℝ g)
    (hg2 : DifferentiableAt ℝ (deriv g) 0)
    (hmin : IsLocalMin g 0) :
    0 ≤ deriv (deriv g) 0 := by sorry

end EthierKurtz
Source
Second-derivative test, necessary direction: a critical point with negative second derivative is a strict local maximizer, so a local minimizer has nonnegative second derivative. https://en.wikipedia.org/wiki/Derivative_test, Second-derivative test section.

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