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Example 1.2 — an explicit M23M_{23}M23​-polynomial unramified outside {2,3,23}\{2,3,23\}{2,3,23}

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MathieuM23.example_1_2

by Lucas · Oct 4, 2026 · Mathlib 0df444a (Lean v4.33.1)

inverse-galois-problemmathieu-groupnumber-theory

Let f=f1.2∈Q[x]f=f_{1.2}\in\mathbb{Q}[x]f=f1.2​∈Q[x] be the degree-23 polynomial of Example 1.2 and let KKK be a splitting field of fff over Q\mathbb{Q}Q. Then:

  1. K/QK/\mathbb{Q}K/Q is Galois;
  2. Gal(K/Q)≅M23\mathrm{Gal}(K/\mathbb{Q})\cong M_{23}Gal(K/Q)≅M23​;
  3. KKK is unramified outside {2,3,23}\{2,3,23\}{2,3,23}: every prime ppp dividing the discriminant dKd_KdK​ belongs to {2,3,23}\{2,3,23\}{2,3,23}.
Gal(K/Q)≅M23,p∣dK ⇒ p∈{2,3,23}.\mathrm{Gal}(K/\mathbb{Q})\cong M_{23},\qquad p\mid d_K\ \Rightarrow\ p\in\{2,3,23\}.Gal(K/Q)≅M23​,p∣dK​ ⇒ p∈{2,3,23}.

A formal proof gives an explicit, independently checkable witness of Theorem 1.1.

Formalization Note The statement is made for every number field KKK that is a splitting field of fff, which does not lose generality because splitting fields are unique up to isomorphism. "Unramified outside SSS" is encoded through the absolute discriminant, which is equivalent by Dedekind's discriminant theorem.

Preamble
import Definitions.Def_MathieuM23_Group
import Definitions.Def_MathieuM23_Polynomials
Formal statement
namespace MathieuM23

theorem example_1_2 (K : Type) [Field K] [NumberField K]
    [Polynomial.IsSplittingField ℚ K fEx12] :
    IsGalois ℚ K ∧ Nonempty ((K ≃ₐ[ℚ] K) ≃* M23) ∧
      ∀ p : ℕ, p.Prime → (p : ℤ) ∣ NumberField.discr K → p = 2 ∨ p = 3 ∨ p = 23 := by sorry

end MathieuM23
Source
X. Huang, B. Jackson, K.-H. Lee, B. Poonen, R. Pries, S. Zhang, *The Mathieu group M23 is a Galois group over Q*, arXiv:2608.08538v1 (2026), https://arxiv.org/abs/2608.08538, p. 1–2, Example 1.2
Read-back

What the Lean code literally says, in plain math · Aristotle (Harmonic) — same agent as the drafter; non-blind

Disclosure — NON-BLIND read-back. This read-back was written by the same agent that drafted the Lean statement (Aristotle, by Harmonic), with full knowledge of the source paper and of the intended meaning. It is not independent, blind testimony and must not be mistaken for an independent audit; a reviewer should compare it against the Lean code directly.

Statement. Let KKK be any type in the lowest universe carrying a field structure that is a number field (characteristic 000 and finite-dimensional over Q\mathbb{Q}Q, with its canonical Q\mathbb{Q}Q-algebra structure). Assume KKK is a splitting field over Q\mathbb{Q}Q of the explicit degree-23 polynomial f1.2f_{1.2}f1.2​. That is, f1.2f_{1.2}f1.2​ splits into linear factors in KKK and KKK is generated over Q\mathbb{Q}Q by its roots. Then all of the following hold:

  1. K/QK/\mathbb{Q}K/Q is a Galois extension;
  2. there is a group isomorphism AutQ(K)≅M23\mathrm{Aut}_{\mathbb{Q}}(K)\cong M_{23}AutQ​(K)≅M23​, where M23=⟨g1,g2⟩M_{23}=\langle g_1,g_2\rangleM23​=⟨g1​,g2​⟩ is the explicit permutation group on {0,…,22}\{0,\dots,22\}{0,…,22} (abstract group isomorphism only);
  3. for every prime natural number ppp, if ppp divides (as an integer) the absolute discriminant dK∈Zd_K\in\mathbb{Z}dK​∈Z of the number field KKK, then p=2p=2p=2, p=3p=3p=3 or p=23p=23p=23.

Here

f1.2=x23−184x21−1150x20+⋯+19169943578802x−3150159884154,f_{1.2}=x^{23}-184x^{21}-1150x^{20}+\dots+19169943578802x-3150159884154,f1.2​=x23−184x21−1150x20+⋯+19169943578802x−3150159884154,

with the full coefficient list in the polynomial definition file. Ramification is not mentioned directly; only the discriminant condition appears. The hypotheses are satisfiable: a splitting field exists and is a number field.

Human review
  • Endorsed by Shuze Chen · Oct 5, 2026

    Confirmed by the moderator at approval.

  • Endorsed by Lucas · Oct 5, 2026

    Confirmed by the mission captain (proposal self-audit).

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