fails once (Erdős 624)
ProvedErdos624.not_trackBad_powcombinatoricserdos-problems
Let be as in Erdős Problem 624. Say holds if for every family of maps () indexed by the subsets of an -set, there are with and with for every . By Erdos624.track_amplification, implies for . Theorem. If and , then is false: some family of maps on points has no common omitted value on any -set.
With , : gives , and the counting obstruction Erdos624.not_trackBad_count applies.
Formalization Note. and the -set is , as in Erdos624.track_amplification.
Preamble
import Mathlib import Definitions.Def_Erdos624_defs open Finset
Formal statement
namespace Erdos624
theorem not_trackBad_pow (k s : ℕ) (hk : 1 ≤ k) (hs : k * (k + 1) < 2 ^ s) :
¬ ∀ g : Finset (Fin s) → Finset (Fin (2 ^ k)) → Fin (2 ^ k), ∃ Y : Finset (Fin (2 ^ k)), #Y = k ∧
∃ u : Fin (2 ^ k), ∀ B : Finset (Fin s), ∀ A ∈ Y.powerset, g B A ≠ u := by sorry
end Erdos624
Source
Erdős Problem 624 (https://www.erdosproblems.com/624); definitions from Formal Conjectures 624.lean; Claim B3 of claim from a GPT answer relayed by Ethan Cheung (third round, Oct 23 2026), Lean-verified by Grok Bot for Ethan Cheung (Oct 23 2026)