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Cauchy–Riemann operators on the cylinder with nondegenerate asymptotics are Fredholm

Proved
CauchyRiemannIndex.isFredholm

by Mazecto · Oct 13, 2026 · Mathlib 0df444a (Lean v4.33.1)

cauchy-riemannconley-zehnder-indexfredholm-indexsobolev-spacessymplectic-geometry

Let 1<p<∞1<p<\infty1<p<∞, let S±S^\pmS± be continuous loops of symmetric matrices and let S:R×S1→R2n×2nS:\mathbb{R}\times S^1\to\mathbb{R}^{2n\times2n}S:R×S1→R2n×2n be continuous with S(s,⋅)→S±S(s,\cdot)\to S^\pmS(s,⋅)→S± uniformly as s→±∞s\to\pm\inftys→±∞; DS=∂s+J0∂t+S(s,t)D_S=\partial_s+J_0\partial_t+S(s,t)DS​=∂s​+J0​∂t​+S(s,t). Assume that the asymptotic operators A±=−J0∂t−S±(t)A^\pm=-J_0\partial_t-S^\pm(t)A±=−J0​∂t​−S±(t) are nondegenerate. Then DS:W1,p(R×S1,R2n)→Lp(R×S1,R2n)D_S:W^{1,p}(\mathbb{R}\times S^1,\mathbb{R}^{2n})\to L^p(\mathbb{R}\times S^1,\mathbb{R}^{2n})DS​:W1,p(R×S1,R2n)→Lp(R×S1,R2n) is Fredholm.

Formalization Note ppp is in ℝ≥0∞ with Fact (1 ≤ p), 1<p1<p1<p and p≠∞p\ne\inftyp=∞. The hypotheses on SSS are IsSymLoop S± and IsAsymptoticTo S Splus Sminus. Nondegeneracy is IsNondegenerate S±: det⁡(Id−Ψ(1))≠0\det(\mathrm{Id}-\Psi(1))\ne0det(Id−Ψ(1))=0 for the fundamental solution Ψ\PsiΨ. "Fredholm" is IsFredholmCR p S: finite-dimensional kernel, closed range, finite-dimensional cokernel.

Preamble
import Definitions.Def_CauchyRiemannIndex_Setting
import Mathlib.Analysis.Calculus.ContDiff.Basic
Formal statement
namespace CauchyRiemannIndex

open MeasureTheory Matrix Filter Topology
open scoped ENNReal NNReal ContDiff RealInnerProductSpace

/-- Wendl, Theorem 4.3 (p. 69), Fredholm property, case `k = 1`, on the cylinder: if `D_S` is
asymptotic to nondegenerate loops `S±` of symmetric matrices and `1 < p < ∞`, then
`D_S : W^{1,p}(ℝ × S¹, ℝ²ⁿ) → L^p(ℝ × S¹, ℝ²ⁿ)` is Fredholm. -/
theorem isFredholm (n : ℕ) (p : ℝ≥0∞) [Fact (1 ≤ p)] (hp : 1 < p) (hp' : p ≠ ⊤)
    (Splus Sminus : ℝ → Mat n) (hSplus : IsSymLoop Splus) (hSminus : IsSymLoop Sminus)
    (S : ℝ × ℝ → Mat n) (hS : IsAsymptoticTo S Splus Sminus) (hplus : IsNondegenerate Splus) (hminus : IsNondegenerate Sminus) :
    IsFredholmCR p S := by
  sorry

end CauchyRiemannIndex
Source
C. Wendl, Lectures on Symplectic Field Theory, arXiv:1612.01009, https://arxiv.org/abs/1612.01009, Lecture 4, Theorem 4.3, p. 69 (case k = 1, cylinder)
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What the Lean code literally says, in plain math · claude-opus-5-5

Read-back: CauchyRiemannIndex.isFredholm

Setting. n∈Nn\in\mathbb Nn∈N; p∈[1,∞]p\in[1,\infty]p∈[1,∞] (instance Fact (1 ≤ p)); loops S±:R→R2n×2nS^\pm:\mathbb R\to\mathbb R^{2n\times2n}S±:R→R2n×2n; coefficient S:R×R→R2n×2nS:\mathbb R\times\mathbb R\to\mathbb R^{2n\times2n}S:R×R→R2n×2n. Matrices are indexed by Fin n ⊕ Fin n; J0=J_0=J0​= Matrix.J =(0−II0)=\begin{pmatrix}0&-I\\ I&0\end{pmatrix}=(0I​−I0​) (checked in Mathlib: fromBlocks 0 (-1) 1 0), i.e. multiplication by iii under (x,y)↦x+iy(x,y)\mapsto x+iy(x,y)↦x+iy.

Hypotheses. 1<p<∞1<p<\infty1<p<∞. S±S^\pmS± are continuous, 1-periodic, pointwise symmetric (IsSymLoop). SSS is continuous, 1-periodic in ttt, and S(s,t)→S±(t)S(s,t)\to S^\pm(t)S(s,t)→S±(t) entrywise uniformly in ttt as s→±∞s\to\pm\inftys→±∞ (IsAsymptoticTo). S±S^\pmS± are nondegenerate: for (every, equivalently the unique) fundamental solution Ψ±\Psi^\pmΨ±, Ψ′=J0S±Ψ\Psi'=J_0S^\pm\PsiΨ′=J0​S±Ψ, Ψ(0)=I\Psi(0)=IΨ(0)=I, one has det⁡(I−Ψ±(1))≠0\det(I-\Psi^\pm(1))\neq0det(I−Ψ±(1))=0.

Definitions used.

  • cylMeasure = Lebesgue on the strip R×[0,1)\mathbb R\times[0,1)R×[0,1); LpCyl n p =Lp(strip;R2n)=L^p(\text{strip};\mathbb R^{2n})=Lp(strip;R2n).
  • W1p p n = closure in Lp×Lp×LpL^p\times L^p\times L^pLp×Lp×Lp (product norm) of the span of triples (u,∂su,∂tu)(u,\partial_su,\partial_tu)(u,∂s​u,∂t​u) with uuu smooth, 1-periodic in ttt, vanishing for ∣s∣>R|s|>R∣s∣>R. This is W1,p(R×S1;R2n)W^{1,p}(\mathbb R\times S^1;\mathbb R^{2n})W1,p(R×S1;R2n) as a graph space; second/third components are the weak derivatives.
  • crApply S (u,v,w)(x) =v(x)+J0w(x)+S(x)u(x)=v(x)+J_0w(x)+S(x)u(x)=v(x)+J0​w(x)+S(x)u(x) (a.e. representatives).
  • crKernel p S = span of {w∈W1,p:DSw=0 a.e. on strip}\{w\in W^{1,p}: D_Sw=0\text{ a.e. on strip}\}{w∈W1,p:DS​w=0 a.e. on strip} (already a subspace).
  • crRange p S = span of {f∈Lp:∃w∈W1,p, f=DSw a.e.}\{f\in L^p:\exists w\in W^{1,p},\ f=D_Sw\text{ a.e.}\}{f∈Lp:∃w∈W1,p, f=DS​w a.e.}.
  • IsFredholmCR p S :=dim⁡Rker⁡<∞ ∧:=\dim_{\mathbb R}\ker<\infty\ \wedge:=dimR​ker<∞ ∧ range closed in LpL^pLp ∧ dim⁡RLp/range⁡<∞\wedge\ \dim_{\mathbb R}L^p/\operatorname{range}<\infty∧ dimR​Lp/range<∞.

Conclusion. DS=∂s+J0∂t+S(s,t):W1,p(R×S1,R2n)→Lp(R×S1,R2n)D_S=\partial_s+J_0\partial_t+S(s,t):W^{1,p}(\mathbb R\times S^1,\mathbb R^{2n})\to L^p(\mathbb R\times S^1,\mathbb R^{2n})DS​=∂s​+J0​∂t​+S(s,t):W1,p(R×S1,R2n)→Lp(R×S1,R2n) has finite-dimensional kernel, closed range and finite-dimensional cokernel.

Degenerate cases. n=0n=0n=0: all spaces are 000; trivially Fredholm. SSS independent of sss (then S=S+=S−S=S^+=S^-S=S+=S− forced by IsAsymptoticTo): DSD_SDS​ is invertible by nondegeneracy, consistent.

Remarks. SSS is not required symmetric for finite sss, as in Wendl (only the asymptotes are). SSS continuous + asymptotically convergent + periodic implies SSS bounded, so DSw∈LpD_Sw\in L^pDS​w∈Lp for w∈W1,pw\in W^{1,p}w∈W1,p and the range set is the genuine image. The redundant Fact (1 ≤ p) is implied by hp.

Soundness checks.

  1. Junk values / coercions / scope.
    • LpL^pLp elements are evaluated through their a.e. representatives; all equalities are =ᵐ[cylMeasure], so the arbitrary values off the strip are irrelevant.
    • IsNondegenerate quantifies over all fundamental solutions; for continuous S±S^\pmS± one exists and is unique (linear ODE), so it is not vacuous.
    • Kernel and cokernel dimensions are real dimensions (FiniteDimensional ℝ).
    • toEuclideanLin M v = M *ᵥ v, standard.
    • All quantifiers are universal over the data; no existential misplacement.
  2. Hypotheses are satisfiable (e.g. n=1n=1n=1, S=c(s)IS=c(s)IS=c(s)I with c→±εc\to\pm\varepsilonc→±ε, 0<ε<2π0<\varepsilon<2\pi0<ε<2π; then Ψ±(1)=\Psi^\pm(1)=Ψ±(1)= rotation by ±ε\pm\varepsilon±ε, nondegenerate). Not vacuous, not trivially true. In that example the kernel is {e−∫0sc v:v∈R2}\{e^{-\int_0^sc}\,v:v\in\mathbb R^2\}{e−∫0s​cv:v∈R2} (2-dimensional, smooth, exponentially decaying, in the closure), cokernel 000; Fredholm as claimed. The statement is Wendl Thm 4.3 (k=1k=1k=1) on the cylinder and is true.

Verdict: no mis-formalization observed

Human review
  • Endorsed by Shuze Chen · Oct 14, 2026

    Confirmed by the moderator at approval.

  • Endorsed by Mazecto · Oct 14, 2026

    Confirmed by the mission captain (proposal self-audit).

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