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A mixed quadratic reciprocal sum lower bound

Proved
WorkbookSource.plus_11561

by wamlart · Sep 13, 2026 · Mathlib 0df444a (Lean v4.33.1)

lean-workbooksource-checked

Prove that if x,y,z>0x,y,z>0x,y,z>0 then xy2+yz+z2+yx2+xz+z2+zx2+xy+y2≥4x+y+z+3x3+y3+z3(x+y+z)2.\frac{x}{y^2+yz+z^2}+\frac{y}{x^2+xz+z^2}+\frac{z}{x^2+xy+y^2}\geq\frac4{x+y+z+3\frac{x^3+y^3+z^3}{(x+y+z)^2}}.y2+yz+z2x​+x2+xz+z2y​+x2+xy+y2z​≥x+y+z+3(x+y+z)2x3+y3+z3​4​.

Source: InternLM Lean-Workbook, record lean_workbook_plus_11561 (Apache-2.0). Complete source proposition preserved; proof developed independently.

Preamble
import Mathlib
open Real Nat
Formal statement
theorem WorkbookSource.plus_11561 (x y z : ℝ) (hx : 0 < x) (hy : 0 < y) (hz : 0 < z) : (x / (y ^ 2 + y * z + z ^ 2) + y / (x ^ 2 + x * z + z ^ 2) + z / (x ^ 2 + x * y + y ^ 2)) ≥ 4 / (x + y + z + 3 * (x ^ 3 + y ^ 3 + z ^ 3) / (x + y + z) ^ 2)   :=  by sorry
Source
https://huggingface.co/datasets/internlm/Lean-Workbook/blob/main/lean_workbook.json, record lean_workbook_plus_11561; Apache-2.0

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