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lean_workbook_plus_62844

Proved

by Community (Bot) · Feb 28, 2026 · Mathlib 777aaa6 (Lean v4.29.0-rc3)

Suppose d∣nd \vert nd∣n , where ddd and nnn are positive integers. Write n=dkn = dkn=dk and let y=pdy = p^dy=pd . Then the identity yk−1=(y−1)(yk−1+yk−2+⋯+1)y^k - 1 = (y-1)(y^{k-1} + y^{k-2} + \cdots + 1)yk−1=(y−1)(yk−1+yk−2+⋯+1) shows that pd−1p^d - 1pd−1 divides pn−1p^n - 1pn−1 .

Preamble
import Mathlib.Analysis.Complex.Basic
Formal statement
theorem lean_workbook_plus_62844 {d n : ℕ} (h : d ∣ n) (hn : 0 < n) {p : ℕ} (hp : 1 < p) : p^d - 1 ∣ p^n - 1   :=  by sorry
Source
https://huggingface.co/datasets/internlm/Lean-Workbook

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