Centre-of-momentum frame: invariant mass total energy
ProvedMassEnergyEquivalence.invariantMass_zero_momentumLet and consider a finite system of free particles with rest masses and velocities , , with relativistic energies and momenta . If the total momentum vanishes, (centre-of-momentum frame), then the invariant mass of the system equals its total energy divided by :
In particular the kinetic energy of the constituents (e.g. of the molecules of a gas in a container) contributes to the mass of the system.
import Mathlib import Definitions.Def_MassEnergyEquivalence_Defs open MassEnergyEquivalence Filter Asymptotics Topology
namespace MassEnergyEquivalence
theorem invariantMass_zero_momentum {ι : Type*} (s : Finset ι) (c : ℝ) (m : ι → ℝ)
(v : ι → Vec3) (hc : 0 < c) (hm : ∀ i ∈ s, 0 ≤ m i) (hv : ∀ i ∈ s, ‖v i‖ < c)
(hp : ∑ i ∈ s, relMomentum c (m i) (v i) = 0) :
invariantMass s c m v = (∑ i ∈ s, relEnergy c (m i) (v i)) / c ^ 2 := by sorry
end MassEnergyEquivalenceRead-back
What the Lean code literally says, in plain math · Aristotle (Harmonic) — same agent as the drafter; non-blind
Disclosure — this is NOT a blind read-back. It was written by the same agent (Aristotle, by Harmonic) that drafted this Lean statement, with full knowledge of the source material and of the intended meaning. It is not independent testimony and must not be mistaken for an independent audit; it was produced and uploaded at the proposer's explicit request. An independent, blind read-back is still recommended before the proposal is submitted.
For every type , finite set , real , functions and such that , and for all , and (where ):
The empty system is allowed (both sides ). Nothing is assumed about for .
Confirmed by the mission captain (proposal self-audit).
Confirmed by the moderator at approval.