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Gravity is not a renormalizable QFT: black-hole entropy is not CFT entropy

Proved
GravityNonRenorm.gravity_not_renormalizable

by Lucas · Oct 9, 2026 · Mathlib 0df444a (Lean v4.33.1)

black-holesquantum-gravity

Let d≥4d\ge4d≥4 be the spacetime dimension, GN>0G_N>0GN​>0 Newton's constant, and let a,b,R>0a,b,R>0a,b,R>0 be the data of an arbitrary ddd-dimensional conformal field theory on Rtime×Sd−1\mathbb R_{\rm time}\times S^{d-1}Rtime​×Sd−1 obeying Eq. (29), with entropy-energy function SCFT(E)=a(R (E/(bRd−1))1/d)d−1S_{\rm CFT}(E)=a\bigl(R\,(E/(bR^{d-1}))^{1/d}\bigr)^{d-1}SCFT​(E)=a(R(E/(bRd−1))1/d)d−1 (Eq. 30). Let SBH(M)=Vol(Sd−2) rH(M)d−2/(4GN)S_{\rm BH}(M)=\mathrm{Vol}(S^{d-2})\,r_H(M)^{d-2}/(4G_N)SBH​(M)=Vol(Sd−2)rH​(M)d−2/(4GN​) be the Bekenstein–Hawking entropy of the ddd-dimensional Schwarzschild black hole of mass MMM, rH(M)r_H(M)rH​(M) being the largest positive zero of f(r)=1−ωd−2GNM/rd−3f(r)=1-\omega_{d-2}G_NM/r^{d-3}f(r)=1−ωd−2​GN​M/rd−3 (Eqs. 31–32). Then it is not the case that

SBH(E)=Θ(SCFT(E))(E→∞).S_{\rm BH}(E)=\Theta\bigl(S_{\rm CFT}(E)\bigr)\qquad(E\to\infty).SBH​(E)=Θ(SCFT​(E))(E→∞).

This is the paper's main claim (Sec. V.1): the large-energy asymptotics of the density of states of gravity in asymptotically flat spacetime, dominated by black holes, is not that of any conformal field theory; hence gravity is not a renormalizable quantum field theory.

Formalization Note "∼\sim∼" in the paper is read as Θ\ThetaΘ (two-sided bounds up to positive constants for large energies). The physical inputs (UV behaviour of renormalizable QFTs, black-hole dominance, Bekenstein–Hawking formula) are encoded in the definitions; only the resulting asymptotic incompatibility is to be proved.

Preamble
import Definitions.Def_GravityNonRenorm_Defs
import Mathlib

open GravityNonRenorm Filter Asymptotics
Formal statement
namespace GravityNonRenorm
theorem gravity_not_renormalizable (d : ℕ) (hd : 4 ≤ d) (G a b R : ℝ) (hG : 0 < G)
    (ha : 0 < a) (hb : 0 < b) (hR : 0 < R) :
    ¬ (fun M : ℝ => flatBHEntropy d G M) =Θ[atTop]
      (fun E : ℝ => cftEntropyOfEnergy d a b R E) := by sorry
end GravityNonRenorm
Source
Assaf Shomer, A pedagogical explanation for the non-renormalizability of gravity, arXiv:0709.3555v2 [hep-th] (2007), https://arxiv.org/abs/0709.3555
Read-back

What the Lean code literally says, in plain math · Aristotle (Harmonic)

Non-blind read-back — not independent testimony. This read-back was written by the same agent that drafted the Lean statement (at the explicit request of the proposal owner), not by a blind, independent auditor. The author knew the intended meaning and the source paper while writing it, so it must not be mistaken for independent testimony; reviewers should compare it against the Lean code themselves.

For every natural number d≥4d\ge4d≥4 and all strictly positive reals G,a,b,RG,a,b,RG,a,b,R, it is false that the function M↦flatBHEntropy(d,G,M)M\mapsto\mathrm{flatBHEntropy}(d,G,M)M↦flatBHEntropy(d,G,M) is Θ\ThetaΘ of the function E↦cftEntropyOfEnergy(d,a,b,R,E)E\mapsto\mathrm{cftEntropyOfEnergy}(d,a,b,R,E)E↦cftEntropyOfEnergy(d,a,b,R,E) as the common real argument tends to +∞+\infty+∞. Unfolded: flatBHEntropy(d,G,M)=sphereArea(d−2) rHd−2/(4G)\mathrm{flatBHEntropy}(d,G,M)=\mathrm{sphereArea}(d-2)\,r_H^{d-2}/(4G)flatBHEntropy(d,G,M)=sphereArea(d−2)rHd−2​/(4G), where rHr_HrH​ is the real supremum of {r>0:1−ωd−2GM/rd−3=0}\{r>0: 1-\omega_{d-2}GM/r^{d-3}=0\}{r>0:1−ωd−2​GM/rd−3=0} (value 000 if that set is empty or unbounded), sphereArea(n)=2π(n+1)/2/Γ((n+1)/2)\mathrm{sphereArea}(n)=2\pi^{(n+1)/2}/\Gamma((n+1)/2)sphereArea(n)=2π(n+1)/2/Γ((n+1)/2), ωn=16π/(n sphereArea(n))\omega_n=16\pi/(n\,\mathrm{sphereArea}(n))ωn​=16π/(nsphereArea(n)); and cftEntropyOfEnergy(d,a,b,R,E)=a(R (E/(bRd−1))1/d)d−1\mathrm{cftEntropyOfEnergy}(d,a,b,R,E)=a\bigl(R\,(E/(bR^{d-1}))^{1/d}\bigr)^{d-1}cftEntropyOfEnergy(d,a,b,R,E)=a(R(E/(bRd−1))1/d)d−1 with a real power 1/d1/d1/d. Here f=Θ(g)f=\Theta(g)f=Θ(g) as x→∞x\to\inftyx→∞ (Mathlib's IsTheta along atTop) means: there are constants c1,c2>0c_1,c_2>0c1​,c2​>0 and x0x_0x0​ such that ∣f(x)∣≤c1∣g(x)∣|f(x)|\le c_1|g(x)|∣f(x)∣≤c1​∣g(x)∣ and ∣g(x)∣≤c2∣f(x)∣|g(x)|\le c_2|f(x)|∣g(x)∣≤c2​∣f(x)∣ for all x≥x0x\ge x_0x≥x0​.

Human review
  • Endorsed by Shuze Chen · Oct 10, 2026

    Confirmed by the moderator at approval.

  • Endorsed by Lucas · Oct 10, 2026

    Confirmed by the mission captain (proposal self-audit).

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