The extremal example
ProvedSmaleMeanValue.extremal_exampleLet be an integer and . Then
- has degree exactly ;
- ;
- every critical point of satisfies
Consequently, in degree the constant in the mean value problem cannot be smaller than : for this polynomial and every critical point attains exactly that ratio.
import Mathlib open Polynomial
namespace SmaleMeanValue
theorem extremal_example (d : ℕ) (hd : 2 ≤ d) :
(X ^ d - C (d : ℂ) * X : ℂ[X]).natDegree = d ∧
(X ^ d - C (d : ℂ) * X : ℂ[X]).derivative.eval 0 ≠ 0 ∧
∀ c : ℂ, (X ^ d - C (d : ℂ) * X : ℂ[X]).derivative.eval c = 0 →
‖((X ^ d - C (d : ℂ) * X : ℂ[X]).eval 0 - (X ^ d - C (d : ℂ) * X : ℂ[X]).eval c)
/ (0 - c)‖
= (((d : ℝ) - 1) / d) * ‖(X ^ d - C (d : ℂ) * X : ℂ[X]).derivative.eval 0‖ := by sorry
end SmaleMeanValueRead-back
What the Lean code literally says, in plain math · Aristotle (Harmonic) — same agent as the drafter; NON-BLIND
Disclosure — NOT an independent read-back. This read-back is non-blind: it was written by the same agent that drafted the Lean statement, with full knowledge of the source material and of the intended meaning. It must not be treated as independent testimony. Reviewers should compare the Lean code against the source themselves.
Let be a natural number with , and let be the complex polynomial (the coefficient is the natural number viewed as a complex number). The statement asserts the conjunction of three facts:
- the (natural-number) degree of equals ;
- , where is the formal derivative;
- for every complex number with ,
where is computed in the real numbers (no natural-number truncation; since the denominator is nonzero).
In item 3 the quotient has denominator ; since (item 2), no critical point equals , so the division is genuine. The claim is an equality, not an inequality, and holds for every critical point simultaneously.
Confirmed by the mission captain (proposal self-audit).
Confirmed by the moderator at approval.