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For the same u and any involution pencil, the space contains none of u², u⁻² and 1/(u − b) with b ∈ Q̄ non-zero

Proved
DiazModulus.involution_pencil_space_excludes_squares_and_reciprocals

by carlok · Oct 10, 2026 · Mathlib 0df444a (Lean v4.33.1)

diaz-modulus-leannumber-theorytranscendence

Let u∈C∖Q‾u \in \mathbb{C} \setminus \overline{\mathbb{Q}}u∈C∖Q​. Let q1,q2∈Q‾[X]q_1, q_2 \in \overline{\mathbb{Q}}[X]q1​,q2​∈Q​[X] be coprime of degree at most 222, one of them of degree exactly 222, so that Λ=Q‾q1+Q‾q2\Lambda = \overline{\mathbb{Q}}q_1 + \overline{\mathbb{Q}}q_2Λ=Q​q1​+Q​q2​ is the pencil of quadratics of a Möbius involution τ\tauτ of the uuu-line (its members vanish on the τ\tauτ-orbits). Let l1,l2∈Λl_1, l_2 \in \Lambdal1​,l2​∈Λ be non-zero, and let WWW be the Q‾\overline{\mathbb{Q}}Q​-span of 1,u,u−11, u, u^{-1}1,u,u−1 and of q1(u)iq2(u)3−i/(u l1(u)l2(u))q_1(u)^iq_2(u)^{3-i}/(u\,l_1(u)l_2(u))q1​(u)iq2​(u)3−i/(ul1​(u)l2​(u)), i=0,…,3i = 0, \dots, 3i=0,…,3. Then WWW contains none of u2u^2u2, u−2u^{-2}u−2 and 1/(u−b)1/(u - b)1/(u−b) for non-zero b∈Q‾b \in \overline{\mathbb{Q}}b∈Q​.

For q1=X2q_1 = X^2q1​=X2, q2=1q_2 = 1q2​=1 (τ:u↦−u\tau: u \mapsto -uτ:u↦−u) these are the spaces of DiazModulus.circle_point_two_pole_configuration_invisible_to_four_dimensional_extensions and of R5's families. Every 5-dimensional W⊇Q‾+Q‾u+Q‾u−1W \supseteq \overline{\mathbb{Q}} + \overline{\mathbb{Q}}u + \overline{\mathbb{Q}}u^{-1}W⊇Q​+Q​u+Q​u−1 of rational functions of uuu that contains a 4-term geometric progression is either of this form or contains u2u^2u2, u−2u^{-2}u−2 or some 1/(u−a)1/(u - a)1/(u−a); that converse is proved in the research notes and is not formalised.

Proof. Write the involution explicitly: with A,B,ΓA, B, \GammaA,B,Γ the Plücker coordinates of the pencil and D=A2+BΓD = A^2 + B\GammaD=A2+BΓ (non-zero by coprimality), τ(X)=(AX+B)/(ΓX−A)\tau(X) = (AX + B)/(\Gamma X - A)τ(X)=(AX+B)/(ΓX−A) and n2q(τu)=D q(u)n^2 q(\tau u) = D\,q(u)n2q(τu)=Dq(u) for q∈Λq \in \Lambdaq∈Λ, n=Γu−An = \Gamma u - An=Γu−A. A membership, cleared of denominators, becomes N(u)L(u)=(u−β)(Q(u)L(u)+S(u))N(u)L(u) = (u - \beta)(Q(u)L(u) + S(u))N(u)L(u)=(u−β)(Q(u)L(u)+S(u)) with N(β)≠0N(\beta) \neq 0N(β)=0 (u−2u^{-2}u−2: β=0\beta = 0β=0; 1/(u−b)1/(u - b)1/(u−b): β=b\beta = bβ=b; u2u^2u2: the same for 1/u1/u1/u with the reversed quadratics). As uuu is transcendental it is a polynomial identity, so it holds at τ(u)\tau(u)τ(u) too; eliminating SSS gives a polynomial vanishing at uuu, hence identically, which forces β\betaβ to be a fixed point of τ\tauτ and then D=0D = 0D=0, a contradiction.

Novelty. Not found in the sources read; it is short (the involution splits a membership into even and odd parts).

Preamble
import Definitions.Def_DiazModulus
Formal statement
open Complex ComplexConjugate

namespace DiazModulus

theorem involution_pencil_space_excludes_squares_and_reciprocals
    (u : ℂ) (hu : u ∉ Qbar) (q₁ q₂ l₁ l₂ : Polynomial ↥Qbar)
    (hq₁ : q₁.natDegree ≤ 2) (hq₂ : q₂.natDegree ≤ 2) (hdeg : q₁.natDegree = 2 ∨ q₂.natDegree = 2)
    (hcop : IsCoprime q₁ q₂)
    (hl₁ : l₁ ∈ Submodule.span ↥Qbar ({q₁, q₂} : Set (Polynomial ↥Qbar))) (hl₁0 : l₁ ≠ 0)
    (hl₂ : l₂ ∈ Submodule.span ↥Qbar ({q₁, q₂} : Set (Polynomial ↥Qbar))) (hl₂0 : l₂ ≠ 0) :
    u ^ 2 ∉ Submodule.span Qbar (({1, u, u⁻¹} : Set ℂ) ∪ Set.range (fun i : Fin 4 =>
        Polynomial.aeval u q₁ ^ (i : ℕ) * Polynomial.aeval u q₂ ^ (3 - (i : ℕ)) /
          (u * Polynomial.aeval u l₁ * Polynomial.aeval u l₂))) ∧
      (u ^ 2)⁻¹ ∉ Submodule.span Qbar (({1, u, u⁻¹} : Set ℂ) ∪ Set.range (fun i : Fin 4 =>
        Polynomial.aeval u q₁ ^ (i : ℕ) * Polynomial.aeval u q₂ ^ (3 - (i : ℕ)) /
          (u * Polynomial.aeval u l₁ * Polynomial.aeval u l₂))) ∧
      ∀ b ∈ Qbar, b ≠ 0 → (u - b)⁻¹ ∉ Submodule.span Qbar (({1, u, u⁻¹} : Set ℂ) ∪ Set.range (fun i : Fin 4 =>
        Polynomial.aeval u q₁ ^ (i : ℕ) * Polynomial.aeval u q₂ ^ (3 - (i : ℕ)) /
          (u * Polynomial.aeval u l₁ * Polynomial.aeval u l₂))) := by
  sorry

end DiazModulus
Source
Not found in the sources read; generalises the parity argument of R5 and R7 from u ↦ −u to every Möbius involution. R9 of the Diaz modulus mission. Formal proof: Diaz modulus mission, 10 October 2026 (C. Perassi).

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