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Bennett two integral summand zero

Proved
D1Bound5.bennett_two_integral_summand_zero

by tp · Oct 24, 2026 · Mathlib 0df444a (Lean v4.33.1)

diophantine-tuplesnumber-theory

The actual column-zero residue summand, with all binomial factors and pole signs, is integral in every subring containing the anchor entries.

Preamble
import Lean.Elab.Tactic.Omega
import Mathlib.Algebra.BigOperators.NatAntidiagonal
import Mathlib.Algebra.Polynomial.BigOperators
import Mathlib.Algebra.Polynomial.Degree.Operations
import Mathlib.Combinatorics.Enumerative.Catalan.Basic
import Mathlib.RingTheory.Binomial
import Mathlib.RingTheory.PowerSeries.Binomial
import Mathlib.Tactic.LinearCombination
import Mathlib.Tactic.NormNum
import Mathlib.Tactic.Ring

Formal statement
section
namespace D1Bound5

variable {F : Type*} [Field F] [CharZero F]


theorem _root_.D1Bound5.bennett_two_integral_summand_zero (S : Subring F)
    (a b c : F) (ha : a ∈ S) (hb : b ∈ S) (hc : c ∈ S)
    (ha0 : a ≠ 0) (hb0 : b ≠ 0)
    (k d0 d1 d2 h0 h1 h2 : ℕ) (hk : 1 ≤ k)
    (hd : d0 + d1 + d2 = 1) (hh : h0 + h1 + h2 + 1 = k + d0) :
    ∃ q ∈ S,
      (((4 : F) ^ k * Ring.choose ((k : F) + 1 / 2) h0) *
        Ring.choose (-((k + d1 : ℕ) : F)) h1 *
        Ring.choose (-((k + d2 : ℕ) : F)) h2) *
      ((a * b * (a - b) ^ 2) ^ k * (a * b * c) ^ (k - h0) *
        ((-b)⁻¹) ^ (k + d1 + h1) * ((-a)⁻¹) ^ (k + d2 + h2)) = 1 * q := by sorry





end D1Bound5
end
Source
D1Bound5/BennettTwoIntegralSummands.lean, lines 8-34, SHA-256 cf848c27c1e7b66b43f1bb2e9f008252599e35de774adedcbacb56ab48e836d3. Project: https://github.com/tomislav-math/d1-bound5-lean

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