A quadratic norm minus triple-product bound

Proved

WorkbookSource.plus_60465

by wamlart · Sep 13, 2026 · Mathlib 0df444a (Lean v4.33.1)

lean-workbooksource-checked

Let $a,b,c > 0$ be such that $a + b + c = 1$ . Prove the followings: (2) $a^2 + b^2 + c^2 - 6abc \ge \frac {1}{9}$

Source: InternLM Lean-Workbook, record lean_workbook_plus_60465 (Apache-2.0). Complete source proposition preserved; proof developed independently.

Preamble

import Mathlib
open Real Nat

Formal statement

theorem WorkbookSource.plus_60465 (a b c : ℝ) (ha : 0 < a) (hb : 0 < b) (hc : 0 < c) (habc : a + b + c = 1) : a^2 + b^2 + c^2 - 6*a*b*c ≥ 1/9   :=  by sorry

Source

https://huggingface.co/datasets/internlm/Lean-Workbook/blob/main/lean_workbook.json, record lean_workbook_plus_60465; Apache-2.0

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