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Friedman's first integral (eq. 17) and conservation of κρR3/3\kappa\rho R^3/3κρR3/3

Proved
CosmoConstCentury.friedman_first_integral

by Lucas · Oct 5, 2026 · Mathlib 0df444a (Lean v4.33.1)

cosmologygeneral-relativitymathematical-physics

Let c>0c>0c>0, let GGG and Λ\LambdaΛ be real constants, and let I⊆RI\subseteq\mathbb RI⊆R be an interval (a preconnected set of times). Let (R,ρ)(R,\rho)(R,ρ) solve the closed (k=1k=1k=1) Friedmann–Lemaître dust equations (15)–(16) on III. Then there is a constant AAA such that for every t∈It\in It∈I:

  1. κ ρ(t) R(t)33=A\dfrac{\kappa\,\rho(t)\,R(t)^3}{3}=A3κρ(t)R(t)3​=A (conservation of mass), and
  2. Friedman's relation (17) holds:
1c2(dRdt)2=A−R+Λ3c2R3R.\frac{1}{c^2}\Big(\frac{dR}{dt}\Big)^2=\frac{A-R+\frac{\Lambda}{3c^2}R^3}{R}.c21​(dtdR​)2=RA−R+3c2Λ​R3​.

Friedman used this integral to show that the magnitude of Λ\LambdaΛ decides whether a matter-filled universe expands monotonically or expands and then contracts.

Formalization Note The predicate IsFriedmannSolution G c Λ k I R ρ requires, at every t∈It\in It∈I, that R(t)>0R(t)>0R(t)>0, that RRR is C2C^2C2 in a neighbourhood of ttt, and that the two equations hold with κ=8πG/c2\kappa=8\pi G/c^2κ=8πG/c2.

Preamble
import Mathlib
import Definitions.Def_CosmoConstCentury_Defs

open Filter Topology
Formal statement
namespace CosmoConstCentury

theorem friedman_first_integral (G c Λ : ℝ) (hc : 0 < c) (I : Set ℝ) (hI : IsPreconnected I)
    (R ρ : ℝ → ℝ) (hsol : IsFriedmannSolution G c Λ 1 I R ρ) :
    ∃ A : ℝ, ∀ t ∈ I, einsteinKappa G c * ρ t * R t ^ 3 / 3 = A ∧
      (1 / c ^ 2) * deriv R t ^ 2 = (A - R t + Λ * R t ^ 3 / (3 * c ^ 2)) / R t := by sorry

end CosmoConstCentury
Source
C. O'Raifeartaigh, M. O'Keeffe, W. Nahm, S. Mitton, "One hundred years of the cosmological constant: from 'superfluous stunt' to dark energy", Eur. Phys. J. H 43, 73-117 (2018), https://doi.org/10.1140/epjh/e2017-80061-7; Section 4, p. 82, eqs. (15), (16), (17) (Friedman 1922).
Read-back

What the Lean code literally says, in plain math · Aristotle (Harmonic)

Disclosure: non-blind read-back. This read-back was written by the same agent that drafted the Lean statement (Aristotle, by Harmonic), at the explicit request of the proposal owner. It is not an independent or blind audit, and it must not be treated as independent testimony: its author knew the source paper and the intended meaning while writing it. Reviewers should compare it against the Lean code themselves.

Let G,c,ΛG,c,\LambdaG,c,Λ be real numbers with c>0c>0c>0; let I⊆RI\subseteq\mathbb RI⊆R be preconnected (an interval, possibly empty, a single point, or unbounded); let R,ρ:R→RR,\rho:\mathbb R\to\mathbb RR,ρ:R→R form a Friedmann solution with k=1k=1k=1 on III: for every t∈It\in It∈I, R(t)>0R(t)>0R(t)>0, RRR is C2C^2C2 near ttt, 3R′(t)2R(t)2+3c2R(t)2−Λ=κc2ρ(t)\dfrac{3R'(t)^2}{R(t)^2}+\dfrac{3c^2}{R(t)^2}-\Lambda=\kappa c^2\rho(t)R(t)23R′(t)2​+R(t)23c2​−Λ=κc2ρ(t) and R′(t)2R(t)2+2R′′(t)R(t)+c2R(t)2−Λ=0\dfrac{R'(t)^2}{R(t)^2}+\dfrac{2R''(t)}{R(t)}+\dfrac{c^2}{R(t)^2}-\Lambda=0R(t)2R′(t)2​+R(t)2R′′(t)​+R(t)2c2​−Λ=0, where κ=8πG/c2\kappa=8\pi G/c^2κ=8πG/c2.

Conclusion: there is a single real number AAA such that for every t∈It\in It∈I,

κ ρ(t) R(t)33=Aand1c2R′(t)2=A−R(t)+ΛR(t)33c2R(t).\frac{\kappa\,\rho(t)\,R(t)^3}{3}=A\qquad\text{and}\qquad \frac{1}{c^2}R'(t)^2=\frac{A-R(t)+\dfrac{\Lambda R(t)^3}{3c^2}}{R(t)}.3κρ(t)R(t)3​=Aandc21​R′(t)2=R(t)A−R(t)+3c2ΛR(t)3​​.

No sign of GGG, Λ\LambdaΛ or ρ\rhoρ is assumed; AAA may be zero or negative.

Human review
  • Endorsed by Shuze Chen · Oct 8, 2026

    Confirmed by the moderator at approval.

  • Endorsed by Lucas · Oct 8, 2026

    Confirmed by the mission captain (proposal self-audit).

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