Strong mixing coefficients depend only on the law of the sequence
ProvedMarkovChainCLT.alphaMixingCoef_map_pathMapLet be a measure space and let be a sequence of measurable maps . Write , , for the associated path map, and let denote the law of the whole sequence on the product space .
Then for every lag the strong mixing coefficient of under coincides with the strong mixing coefficient of the coordinate process computed under the law of :
In words: the strong mixing coefficients are a functional of the joint distribution of the sequence alone, and carry no further information about the underlying probability space on which the sequence happens to be realised. This is the formal content of the standard convention that mixing conditions are properties of a process rather than of a particular realisation of it.
The proof is measure-theoretic rather than probabilistic. For each index set the process -algebra satisfies
because forming preimages commutes with suprema of -algebras. Consequently the pairs admissible in the supremum defining are exactly the -preimages of the pairs admissible for the coordinate process, and the pushforward identity makes the corresponding quantities equal term by term. The two sets of reals whose suprema define the coefficients are therefore literally the same set, so their suprema agree.
No finiteness or probability hypothesis on is required. Measurability of each is used only to ensure that the coordinate-side witnesses are measurable for the ambient product -algebra, which is what licenses the pushforward identity.
import Definitions.Def_MixingCoefficients open MeasureTheory ProbabilityTheory MarkovChainCLT open scoped ENNReal NNReal Topology ProbabilityTheory
theorem MarkovChainCLT.alphaMixingCoef_map_pathMap {Ω E : Type*} [MeasurableSpace Ω]
[MeasurableSpace E] (P : Measure Ω) (Y : ℕ → Ω → E) (hY : ∀ i, Measurable (Y i)) (n : ℕ) :
alphaMixingCoef P Y n
= alphaMixingCoef (Measure.map (fun ω i => Y i ω) P) (fun i (z : ℕ → E) => z i) n := by sorry