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Coordinatewise Hamming character transform

Proved
CodingTheory.hammingCoordinateCharacterSum

by Rui Chao · Sep 9, 2026 · Mathlib 0df444a (Lean v4.33.1)

charactersumscodingtheoryerror-correctingcodesfinitefieldsweightenumerator

Let FFF be a finite field of cardinality qqq, let ι\iotaι be a finite coordinate type of cardinality nnn, and let ψ:F→C\psi:F\to\mathbb Cψ:F→C be a primitive additive character. For every word c∈Fιc\in F^\iotac∈Fι and all X,Y∈CX,Y\in\mathbb CX,Y∈C,

∑v∈FιXn−wt⁡(v)Ywt⁡(v)ψ(⟨c,v⟩)=(X+(q−1)Y)n−wt⁡(c)(X−Y)wt⁡(c).\sum_{v\in F^\iota} X^{n-\operatorname{wt}(v)}Y^{\operatorname{wt}(v)} \psi(\langle c,v\rangle) = \bigl(X+(q-1)Y\bigr)^{n-\operatorname{wt}(c)} \bigl(X-Y\bigr)^{\operatorname{wt}(c)}.v∈Fι∑​Xn−wt(v)Ywt(v)ψ(⟨c,v⟩)=(X+(q−1)Y)n−wt(c)(X−Y)wt(c).

This identity packages the coordinatewise finite-field transform used in the complete- and Hamming-weight-enumerator identities as an independently reusable statement.

Preamble
import Definitions.Def_CodingTheory
import Mathlib.NumberTheory.LegendreSymbol.Complex
Formal statement
namespace CodingTheory

open scoped BigOperators

/-- The coordinatewise character sum that produces the MacWilliams variable transform. -/
theorem hammingCoordinateCharacterSum
    (F ι : Type*) [Field F] [Fintype F] [DecidableEq F]
    [Fintype ι] [DecidableEq ι]
    (ψ : AddChar F ℂ) (hψ : ψ.IsPrimitive)
    (c : Word F ι) (X Y : ℂ) :
    (∑ v : Word F ι,
        X ^ (Fintype.card ι - hammingNorm v) * Y ^ hammingNorm v *
          ψ ((dotForm F ι) c v)) =
      (X + ((Fintype.card F - 1 : ℕ) : ℂ) * Y) ^
          (Fintype.card ι - hammingNorm c) *
        (X - Y) ^ hammingNorm c := by sorry

end CodingTheory
Source
F. J. MacWilliams and N. J. A. Sloane, The Theory of Error-Correcting Codes, Chapter 5, Lemma 9, p. 143, proof of Theorem 10, pp. 144–145, and proof of Theorem 13, p. 146, https://books.google.com/books?id=nv6WCJgcjxcC, chapter DOI: 10.1016/S0924-6509(08)70530-0; Violetta Weger, Coding Theory, Definition 11.10 and Lemma 11.11, pp. 157–158, and polynomial formula p. 159, https://home.cit.tum.de/~wvi/CT.pdf
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What the Lean code literally says, in plain math · gpt-5.6-sol

For every pair of types FFF and ι\iotaι, assuming that FFF is a field equipped with a finite enumeration and decidable equality and that ι\iotaι is equipped with a finite enumeration and decidable equality, let ψ:F→C\psi:F\to\mathbb Cψ:F→C be an additive character—meaning ψ(0)=1\psi(0)=1ψ(0)=1 and ψ(a+b)=ψ(a)ψ(b)\psi(a+b)=\psi(a)\psi(b)ψ(a+b)=ψ(a)ψ(b) for all a,b∈Fa,b\in Fa,b∈F—which is primitive in the precise sense that, for every nonzero a∈Fa\in Fa∈F, the character x↦ψ(ax)x\mapsto\psi(ax)x↦ψ(ax) is not the constant-one character. For every arbitrary word c:ι→Fc:\iota\to Fc:ι→F (with no requirement that ccc belong to any code) and every X,Y∈CX,Y\in\mathbb CX,Y∈C, define wt⁡(u)=∣{i∈ι:u(i)≠0}∣\operatorname{wt}(u)=|\{i\in\iota:u(i)\ne0\}|wt(u)=∣{i∈ι:u(i)=0}∣. Then

∑v:ι→FX∣ι∣−wt⁡(v)Ywt⁡(v)ψ ⁣(∑i∈ιc(i)v(i))=(X+((∣F∣−1)N)CY)∣ι∣−wt⁡(c)(X−Y)wt⁡(c).\sum_{v:\iota\to F} X^{|\iota|-\operatorname{wt}(v)} Y^{\operatorname{wt}(v)} \psi\!\left(\sum_{i\in\iota}c(i)v(i)\right) = \left(X+\bigl((|F|-1)_{\mathbb N}\bigr)_{\mathbb C}Y\right)^{|\iota|-\operatorname{wt}(c)} (X-Y)^{\operatorname{wt}(c)}.v:ι→F∑​X∣ι∣−wt(v)Ywt(v)ψ(i∈ι∑​c(i)v(i))=(X+((∣F∣−1)N​)C​Y)∣ι∣−wt(c)(X−Y)wt(c).

The sum ranges over all functions v:ι→Fv:\iota\to Fv:ι→F, not over a specified code, and the argument of ψ\psiψ is the coordinatewise dot product ∑i∈ιc(i)v(i)\sum_{i\in\iota}c(i)v(i)∑i∈ι​c(i)v(i) in FFF. Every exponent is a natural number; each subtraction in an exponent is natural-number subtraction, which is truncated at zero, although wt⁡(u)≤∣ι∣\operatorname{wt}(u)\le|\iota|wt(u)≤∣ι∣ because it counts a subset of the coordinates. Likewise, ∣F∣−1|F|-1∣F∣−1 is computed in N\mathbb NN before being coerced into C\mathbb CC; the field assumptions make FFF nontrivial, so its finite cardinality is at least two. The statement includes the case ι=∅\iota=\varnothingι=∅, arbitrary zero or nonzero values of XXX and YYY, and zero exponents, with complex natural powers using the convention Z0=1Z^0=1Z0=1, including 00=10^0=100=1.

Human review
  • Endorsed by Shuze Chen · Sep 10, 2026

  • Endorsed by Rui Chao · Sep 10, 2026

    Confirmed by the mission captain (proposal self-audit).

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