A cyclic pairwise ratio bound at fixed sum three

Proved

WorkbookSource.base_9289

by wamlart · Sep 13, 2026 · Mathlib 0df444a (Lean v4.33.1)

lean-workbooksource-checked

For $a, b, c>0, a+b+c=3$ , prove that $\frac{a}{a+b}+\frac{b}{b+c}+\frac{c}{c+a}\ge\frac{3(a^2+b^2+c^2)}{3+a^3+b^3+c^3}$

Source: InternLM Lean-Workbook, record lean_workbook_9289 (Apache-2.0). Complete source proposition preserved; proof developed independently.

Preamble

import Mathlib
open Real Nat

Formal statement

theorem WorkbookSource.base_9289 (a b c : ℝ) (ha : 0 < a) (hb : 0 < b) (hc : 0 < c) (hab : a + b + c = 3) : a / (a + b) + b / (b + c) + c / (c + a) ≥ 3 * (a ^ 2 + b ^ 2 + c ^ 2) / (3 + a ^ 3 + b ^ 3 + c ^ 3)  :=  by sorry

Source

https://huggingface.co/datasets/internlm/Lean-Workbook/blob/main/lean_workbook.json, record lean_workbook_9289; Apache-2.0

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