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The max-rule cascade RmR_mRm​ never becomes tree-safe

Proved
Erdos195.max_rule_cascade

by Ethan Cheung Wang · Oct 23, 2026 · Mathlib 0df444a (Lean v4.33.1)

arithmetic-progressionscombinatoricserdos-problems

Tree orders: for a tree witness θ(k,r)∈{0,1}\theta(k,r)\in\{0,1\}θ(k,r)∈{0,1} and distinct integers x,yx,yx,y with k=ν2(y−x)k=\nu_2(y-x)k=ν2​(y−x), x≺θyx\prec_\theta yx≺θ​y iff bitk(x)=θ(k, x mod 2k)\mathrm{bit}_k(x)=\theta(k,\,x\bmod 2^k)bitk​(x)=θ(k,xmod2k). A finite word QQQ is θ\thetaθ-safe if "QQQ in order, then all other integers in ≺θ\prec_\theta≺θ​-order" has no monotone 444-term arithmetic progression; it is tree-safe if it is θ\thetaθ-safe for some θ\thetaθ. An in-order pair aaa before bbb in QQQ is open if 2b−a,3b−2a∉Q2b-a,3b-2a\notin Q2b−a,3b−2a∈/Q. Let P∗=(0,1,−1,−5)P^*=(0,1,-1,-5)P∗=(0,1,−1,−5). For m≥0m\ge0m≥0 let wj=2⋅3j+1−1w_j=2\cdot3^{j+1}-1wj​=2⋅3j+1−1 and Rm=(0,1,−1,5,3,2,w1,…,wm)R_m=(0,1,-1,5,3,2,w_1,\dots,w_m)Rm​=(0,1,−1,5,3,2,w1​,…,wm​) (note w0=5w_0=5w0​=5). Then every in-order 333-AP a,b,2b−aa,b,2b-aa,b,2b−a of RmR_mRm​ has 3b−2a∈Rm3b-2a\in R_m3b−2a∈Rm​ before 2b−a2b-a2b−a; the pairs (1,−1)(1,-1)(1,−1) and (−1,wm)(-1,w_m)(−1,wm​) are open, at the same node (1, 1 mod 2)(1,\,1\bmod 2)(1,1mod2), with opposite bits; hence

Rm is not tree-safe;R_m\ \text{is not tree-safe};Rm​ is not tree-safe;

and the fourth term of (−1,wm)(-1,w_m)(−1,wm​) is 3wm+2=wm+1>max⁡Rm3w_m+2=w_{m+1}>\max R_m3wm​+2=wm+1​>maxRm​. So the rule "close the conflict at the maximum by its fourth term" runs forever.

Formalization note: treeLt is from Definitions.Def_Erdos195_tree; Safe, bitOne from Definitions.Def_Erdos195_defs; positions are List.idxOf, ν2\nu_2ν2​ is padicValInt 2, L <+: Q means LLL is a prefix of QQQ.

Preamble
import Mathlib
import Definitions.Def_Erdos195_tree
Formal statement
namespace Erdos195

theorem max_rule_cascade (m : ℕ) (R : List ℤ)
    (hR : R = [0, 1, -1, 5, 3, 2] ++ (List.range m).map (fun j : ℕ => (2 : ℤ) * 3 ^ (j + 2) - 1))
    (w : ℤ) (hw : w = 2 * 3 ^ (m + 1) - 1) :
    (∀ a b : ℤ, a ∈ R → b ∈ R → 2 * b - a ∈ R → R.idxOf a < R.idxOf b →
        R.idxOf b < R.idxOf (2 * b - a) →
        3 * b - 2 * a ∈ R ∧ R.idxOf (3 * b - 2 * a) < R.idxOf (2 * b - a)) ∧
    w ∈ R ∧ R.idxOf 1 < R.idxOf (-1) ∧ R.idxOf (-1) < R.idxOf w ∧
    2 * (-1) - 1 ∉ R ∧ 3 * (-1) - 2 * 1 ∉ R ∧ 2 * w - (-1) ∉ R ∧ 3 * w - 2 * (-1) ∉ R ∧
    padicValInt 2 (-1 - 1) = 1 ∧ padicValInt 2 (w - (-1)) = 1 ∧
    (1 : ℤ) % 2 ^ 1 = (-1) % 2 ^ 1 ∧ ¬ (bitOne (-1) 1 ↔ bitOne w 1) ∧
    (¬ ∃ θ : ℕ → ℤ → Bool, Safe (treeLt θ) R) ∧
    3 * w - 2 * (-1) = 2 * 3 ^ (m + 2) - 1 ∧ ∀ x ∈ R, x < 3 * w - 2 * (-1) := by sorry

end Erdos195
Source
Erdős Problem 195 (https://www.erdosproblems.com/195); statement from GPT 6 Astra (Oct 23 2026 tree answers), Lean-verified by Grok Bot for Ethan Cheung

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