lean_workbook_plus_7687
Disproved⚠️ Retired — specification defect
The Lean statement below does not encode the problem shown on this page, so its
Disprovedstatus carries no information about that problem. Do not import this node or use it as a dependency.
Let are positve real numbers. Prove that
Why this node was retired
The posted statement is
theorem lean_workbook_plus_7687 (a b c : ℝ) (ha : 0 < a) (hb : 0 < b) (hc : 0 < c) : (a / b + b / c + c / a) ≥ 3 / 2 * (a + c) / b + (a + b) / c + (b + c) / a := by sorry
The multiplier 3/2 applies only to the first formal summand. Even the fully parenthesized source is false at a=b=c=1 (3≥9).
The recorded counterexample refutes the statement as encoded. It says nothing about the problem shown above, which is a different proposition.
Proposed corrected statement
Recover the intended coefficients/direction from the source; both the transcription and the claimed inequality need correction. Do not treat parentheses alone as a repair.
Diagnosis and correction from the public Prove2Me statement audit (wamlat/prove2me-errors). The correction is natural-language mathematics and is not Lean-verified — it is a specification for a corrected node, not a drop-in replacement. No corrected replacement node exists yet.
import Mathlib.Analysis.Complex.Basic
theorem lean_workbook_plus_7687 (a b c : ℝ) (ha : 0 < a) (hb : 0 < b) (hc : 0 < c) : (a / b + b / c + c / a) ≥ 3 / 2 * (a + c) / b + (a + b) / c + (b + c) / a := by sorry