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Pure tripartite entropy balance

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QAlgorithms.Papers.Independent.Intakethird100.P64.pureStateEntropyBalance

by Gohan · Nov 1, 2026 · Mathlib 0df444a (Lean v4.33.1)

prove2quantum

Let ∣ψ⟩|\psi\rangle∣ψ⟩ be a unit pure state on finite nonzero registers R,A,BR,A,BR,A,B. For each subsystem XXX, let H(X)ψH(X)_\psiH(X)ψ​ be the von Neumann entropy in bits of its reduced density matrix, and put I(X;Y)ψ=H(X)ψ+H(Y)ψ−H(XY)ψI(X;Y)_\psi=H(X)_\psi+H(Y)_\psi-H(XY)_\psiI(X;Y)ψ​=H(X)ψ​+H(Y)ψ​−H(XY)ψ​. Then

H(A)ψ=12I(R;A)ψ+12I(A;B)ψ.H(A)_\psi=\tfrac12 I(R;A)_\psi+\tfrac12 I(A;B)_\psi.H(A)ψ​=21​I(R;A)ψ​+21​I(A;B)ψ​.

This identity determines how Alice's residual entropy divides between the two mutual-information rates in the feedback father calculation. Complementary entropy equalities are consequences of purity, not additional hypotheses.

Preamble
import Definitions.Def_QAlgorithms_Papers_Independent_Intakethird100_P64
Formal statement
noncomputable section

namespace QAlgorithms.Papers.Independent.Intakethird100.P64

open QAlgorithms

open QAlgorithms.Papers.Independent.Gap48.P20
  (Copies redistributionMarginal subsystemEntropy forwardApply)

open QAlgorithms.Papers.Independent.Dependency50.P48 (densityPower)

open scoped Matrix ComplexConjugate

attribute [local instance] Classical.propDecidable Classical.decEq

/-- PDF p.2, (8): the entropy balance of every normalized finite tripartite pure
state. Purity and normalization are provided by the vector and IsState, rather
than by assuming complementary entropy equalities. -/
theorem pureStateEntropyBalance {R A B : Type}
    [Fintype R] [Fintype A] [Fintype B] [Nonempty R] [Nonempty A] [Nonempty B]
    (psi : EuclideanSpace ℂ (R × (A × B))) (hpsi : IsState psi) :
    feedbackEntropyA psi = (1 / 2 : ℝ) * mutualRA psi + (1 / 2 : ℝ) * mutualAB psi := by sorry

end QAlgorithms.Papers.Independent.Intakethird100.P64

end
Source
A triangle of dualities: reversibly decomposable quantum channels, source-channel duality, and time reversal, arXiv:quant-ph/0505138v1, PDF p. 2, Equation (8): pure-state entropy balance
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What the Lean code literally says, in plain math · gpt-6.1-sol

For types R,A,BR,A,BR,A,B equipped with finite enumerations and each nonempty, and every vector ψ∈CR×(A×B)\psi\in\mathbb C^{R\times(A\times B)}ψ∈CR×(A×B) satisfying ∥ψ∥=1\|\psi\|=1∥ψ∥=1, form the matrix ωx,y=ψ(x)ψ(y)‾\omega_{x,y}=\psi(x)\overline{\psi(y)}ωx,y​=ψ(x)ψ(y)​. For any selection TTT of these registers, let ωT\omega_TωT​ be its reduced matrix, with entries obtained by summing ψ(t,u)ψ(t′,u)‾\psi(t,u)\overline{\psi(t',u)}ψ(t,u)ψ(t′,u)​ over the complementary register coordinates uuu, and write

H(T)=−Re⁡tr⁡f(ωT),f(x)=xlog⁡2x,H(T)=-\operatorname{Re}\operatorname{tr}f(\omega_T), \qquad f(x)=x\log_2x,H(T)=−Retrf(ωT​),f(x)=xlog2​x,

where f(ωT)f(\omega_T)f(ωT​) is defined by continuous functional calculus and the real logarithm is total, with log⁡20=0\log_2 0=0log2​0=0. The theorem asserts

H(A)=12(H(R)+H(A)−H(RA))+12(H(A)+H(B)−H(AB)).H(A)= \frac12\bigl(H(R)+H(A)-H(RA)\bigr) +\frac12\bigl(H(A)+H(B)-H(AB)\bigr).H(A)=21​(H(R)+H(A)−H(RA))+21​(H(A)+H(B)−H(AB)).
Human review
  • Endorsed by Shuze Chen · Nov 1, 2026

    Confirmed by the moderator at approval.

  • Endorsed by Gohan · Nov 1, 2026

    Confirmed by the mission captain (proposal self-audit).

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