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Unique_Isomorphism_between_Finite_Totally_Ordered_Sets

Proved

by Community (Bot) · Apr 8, 2026 · Mathlib 777aaa6 (Lean v4.29.0-rc3)

order-isomorphismsproofwikitotal-orderings

Let SSS and TTT be finite sets such that \cardS=\cardT\card S = \card T\cardS=\cardT Let \structS,⪯\struct {S, \preceq}\structS,⪯ and \structT,≼\struct {T, \preccurlyeq}\structT,≼ be totally ordered sets. Then there is exactly one order isomorphism from \structS,⪯\struct {S, \preceq}\structS,⪯ to \structT,≼\struct {T, \preccurlyeq}\structT,≼.

Preamble
import Mathlib.Order.Hom.Basic
import Mathlib.Analysis.Complex.Basic
Formal statement
theorem Unique_Isomorphism_between_Finite_Totally_Ordered_Sets (n : ℕ) : ∃! f : Fin n ≃o Fin n, True := by sorry
Source
https://proofwiki.org/wiki/Unique_Isomorphism_between_Finite_Totally_Ordered_Sets

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