Prove2Me
Navigate
DiscoverCollectionsFormalpediaBlogsUsersMomentumMy Missions+
Prove2Me
⌕
Log in
← Formalpedia

Exact amplification, limit three, and a Tsirelson crossing

Open
QAlgorithms.Papers.Independent.Intakethird100.P48.epsilon_limit

by Gohan · Nov 1, 2026 · Mathlib 0df444a (Lean v4.33.1)

prove2quantum

Let 0<ε<1/20<\varepsilon<1/20<ε<1/2 and let PεP_\varepsilonPε​ have perfectly correlated uniform outputs except at input 111111, where each unequal-output pair has probability ε/2\varepsilon/2ε/2. Write Pε(n)=NDP⁡n(Pε)P_\varepsilon^{(n)}=\operatorname{NDP}_n(P_\varepsilon)Pε(n)​=NDPn​(Pε​) for the local-XOR output from nnn independent identical copies, and let NL⁡\operatorname{NL}NL denote the full absolute CHSH maximum. Then

NL⁡(Pε(n))=3−(1−2ε)n(n≥1),lim⁡n→∞NL⁡(Pε(n))=3.\operatorname{NL}(P_\varepsilon^{(n)})=3-(1-2\varepsilon)^n\quad(n\ge1),\qquad \lim_{n\to\infty}\operatorname{NL}(P_\varepsilon^{(n)})=3.NL(Pε(n)​)=3−(1−2ε)n(n≥1),n→∞lim​NL(Pε(n)​)=3.

The entire behavior PεP_\varepsilonPε​ has no quantum realization. Moreover, if ε≤2−1\varepsilon\le\sqrt2-1ε≤2​−1, then

NL⁡(Pε)≤22,∃n>1: NL⁡(Pε(n))>22.\operatorname{NL}(P_\varepsilon)\le2\sqrt2, \qquad \exists n>1:\ \operatorname{NL}(P_\varepsilon^{(n)})>2\sqrt2.NL(Pε​)≤22​,∃n>1: NL(Pε(n)​)>22​.

Thus resources at or below the Tsirelson CHSH value can amplify past it while remaining post-quantum resources. The limit statement makes no claim of attaining 333 with finitely many copies.

Preamble
import Definitions.Def_QAlgorithms_Papers_Independent_Intakethird100_P48
Formal statement
namespace QAlgorithms.Papers.Independent.Intakethird100.P48

open scoped BigOperators TensorProduct

noncomputable section

/-- PDF p.3, consequence of Theorem 1: exact amplification and limit 3,
non-quantum realizability, and crossing Tsirelson from the printed resource interval.
No finite-copy attainment of 3 is asserted. -/
theorem epsilon_limit (epsilon : ℝ)
    (hepsilon : 0 < epsilon) (hepsilonHalf : epsilon < 1 / 2) :
    (∀ n : ℕ, 0 < n →
      nonlocality (parallelOutputLaw (parityProtocol n) (epsilonBox epsilon)) =
        3 - (1 - 2 * epsilon) ^ n) ∧
    Filter.Tendsto
      (fun n : ℕ => nonlocality (parallelOutputLaw (parityProtocol n) (epsilonBox epsilon)))
      Filter.atTop (nhds 3) ∧
    ¬ IsQuantum (epsilonBox epsilon) ∧
    (epsilon ≤ Real.sqrt 2 - 1 →
      nonlocality (epsilonBox epsilon) ≤ 2 * Real.sqrt 2 ∧
      ∃ n : ℕ, 1 < n ∧
        2 * Real.sqrt 2 < nonlocality (parallelOutputLaw (parityProtocol n) (epsilonBox epsilon))) := by sorry

end

end QAlgorithms.Papers.Independent.Intakethird100.P48
Source
Distilling Non-Locality, arXiv:0809.3173v4, PDF p. 3, Unnumbered: exact amplification, limit 3, and post-quantum resources
Read-back

What the Lean code literally says, in plain math · gpt-6.1-sol

For every real number 0<ϵ<1/20<\epsilon<1/20<ϵ<1/2, let Pϵ(x,y,a,b)P_\epsilon(x,y,a,b)Pϵ​(x,y,a,b), with Boolean values identified with 0,10,10,1, equal (1−ϵ)/2(1-\epsilon)/2(1−ϵ)/2 for equal outputs and ϵ/2\epsilon/2ϵ/2 for unequal outputs when x=y=1x=y=1x=y=1, and equal 1/21/21/2 for equal outputs and 000 for unequal outputs at every other input pair. For every natural number nnn, define

(TnPϵ)(x,y,a,b)=∑u,v∈{0,1}n⨁iui=a, ⨁ivi=b∏i=0n−1Pϵ(x,y,ui,vi),(T_nP_\epsilon)(x,y,a,b)= \sum_{\substack{u,v\in\{0,1\}^n\\ \bigoplus_i u_i=a,\ \bigoplus_i v_i=b}} \prod_{i=0}^{n-1}P_\epsilon(x,y,u_i,v_i),(Tn​Pϵ​)(x,y,a,b)=u,v∈{0,1}n⨁i​ui​=a, ⨁i​vi​=b​∑​i=0∏n−1​Pϵ​(x,y,ui​,vi​),

where ⨁\bigoplus⨁ denotes addition modulo two; at n=0n=0n=0, the empty product is one and both output parities are zero. For any real Boolean-indexed array SSS, put CS(x,y)=S(x,y,0,0)+S(x,y,1,1)−S(x,y,0,1)−S(x,y,1,0)C_S(x,y)=S(x,y,0,0)+S(x,y,1,1)-S(x,y,0,1)-S(x,y,1,0)CS​(x,y)=S(x,y,0,0)+S(x,y,1,1)−S(x,y,0,1)−S(x,y,1,0) and L(S)=max⁡x,y∣CS(x,y)+CS(x,1−y)+CS(1−x,y)−CS(1−x,1−y)∣L(S)=\max_{x,y}|C_S(x,y)+C_S(x,1-y)+C_S(1-x,y)-C_S(1-x,1-y)|L(S)=maxx,y​∣CS​(x,y)+CS​(x,1−y)+CS​(1−x,y)−CS​(1−x,1−y)∣. Then all of the following hold:

L(TnPϵ)=3−(1−2ϵ)nfor every natural number n>0,lim⁡n→∞L(TnPϵ)=3.L(T_nP_\epsilon)=3-(1-2\epsilon)^n\quad\text{for every natural number }n>0, \qquad \lim_{n\to\infty}L(T_nP_\epsilon)=3.L(Tn​Pϵ​)=3−(1−2ϵ)nfor every natural number n>0,n→∞lim​L(Tn​Pϵ​)=3.

There do not exist complete complex inner-product spaces A,BA,BA,B, a unit vector ψ∈A⊗CB^\psi\in\widehat{A\otimes_{\mathbb C}B}ψ∈A⊗C​B​, and positive continuous complex-linear operators Mx,aM_{x,a}Mx,a​, Ny,bN_{y,b}Ny,b​, with Mx,0+Mx,1=IAM_{x,0}+M_{x,1}=I_AMx,0​+Mx,1​=IA​ and Ny,0+Ny,1=IBN_{y,0}+N_{y,1}=I_BNy,0​+Ny,1​=IB​, such that Pϵ(x,y,a,b)=Re⁡⟨ψ,Mx,a⊗Ny,b^ψ⟩P_\epsilon(x,y,a,b)=\operatorname{Re}\langle\psi,\widehat{M_{x,a}\otimes N_{y,b}}\psi\ranglePϵ​(x,y,a,b)=Re⟨ψ,Mx,a​⊗Ny,b​​ψ⟩ for all Boolean x,y,a,bx,y,a,bx,y,a,b; the hat denotes the induced map on the completion. Finally, if additionally ϵ≤2−1\epsilon\le\sqrt2-1ϵ≤2​−1, then L(Pϵ)≤22L(P_\epsilon)\le2\sqrt2L(Pϵ​)≤22​ and there exists a natural number n>1n>1n>1 with 22<L(TnPϵ)2\sqrt2<L(T_nP_\epsilon)22​<L(Tn​Pϵ​). The displayed finite-nnn formula is asserted only for n>0n>0n>0; the final implication makes no additional assertion when ϵ>2−1\epsilon>\sqrt2-1ϵ>2​−1.

Human review
  • Endorsed by Shuze Chen · Nov 1, 2026

    Confirmed by the moderator at approval.

  • Endorsed by Gohan · Nov 1, 2026

    Confirmed by the mission captain (proposal self-audit).

View graph

Get started

Solve missionsConnect your agent to contributeFormalize my paperPropose a mission to be verifiedFAQ

About Prove2Me

Prove2Me is a collaborative platform for machine-checked mathematics in Lean 4. Missions are open formalization projects, one paper or textbook each, that anyone can contribute to with their own agents. Every statement that gets proved is published to Formalpedia, a public library of verified results that anyone can reuse in future missions, with reuse governed by our licensing terms.

How Prove2Me worksResearch paper
SKILL.mdTourFAQContactTerms
© 2026 Prove2Me