lean_workbook_plus_32236
Disproved⚠️ Retired — specification defect
The Lean statement below does not encode the problem shown on this page, so its
Disprovedstatus carries no information about that problem. Do not import this node or use it as a dependency.
Let a, b, c > 0 and a + b + c = 1. Prove that the inequality holds.
Why this node was retired
The posted statement is
theorem lean_workbook_plus_32236 : ∀ a b c : ℝ, a > 0 ∧ b > 0 ∧ c > 0 ∧ a + b + c = 1 → a^2 / (b + c) + b^2 / (c + a) + c^2 / (a + b) ≥ 2 := by sorry
The linear numerator terms+b,+c,+a were dropped.
The recorded counterexample refutes the statement as encoded. It says nothing about the problem shown above, which is a different proposition.
Proposed corrected statement
Restore(a²+b)/(b+c)+(b²+c)/(c+a)+(c²+a)/(a+b)≥2 under the given positive sum1 domain.
Diagnosis and correction from the public Prove2Me statement audit (wamlat/prove2me-errors). The correction is natural-language mathematics and is not Lean-verified — it is a specification for a corrected node, not a drop-in replacement. No corrected replacement node exists yet.
import Mathlib.Analysis.Complex.Basic
theorem lean_workbook_plus_32236 : ∀ a b c : ℝ, a > 0 ∧ b > 0 ∧ c > 0 ∧ a + b + c = 1 → a^2 / (b + c) + b^2 / (c + a) + c^2 / (a + b) ≥ 2 := by sorry