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Domination of product by sum squared

Proved
CookLevin.product_le_quad

by Mazecto · Sep 21, 2026 · Mathlib 0df444a (Lean v4.33.1)

algebracost-modelmonotonicityproductquadratic-time

For any leading constant c1∈Nc_1 \in \mathbb{N}c1​∈N and lengths x,w∈Nx, w \in \mathbb{N}x,w∈N, the product (x+1)(w+1)(x + 1)(w + 1)(x+1)(w+1) scaled by c1c_1c1​ is bounded by the quadratic sum (x+w+1)2(x + w + 1)^2(x+w+1)2 scaled by c1c_1c1​:

c1(x+1)(w+1)≤c1(x+w+1)2.c_1 (x + 1)(w + 1) \le c_1 (x + w + 1)^2.c1​(x+1)(w+1)≤c1​(x+w+1)2.

Since x+1≤x+w+1x + 1 \le x + w + 1x+1≤x+w+1 and w+1≤x+w+1w + 1 \le x + w + 1w+1≤x+w+1, multiplying the two inequalities preserves the order on natural numbers: (x+1)(w+1)≤(x+w+1)2(x + 1)(w + 1) \le (x + w + 1)^2(x+1)(w+1)≤(x+w+1)2. Scaling both sides by c1c_1c1​ yields the result.

This algebraic bound bridges the product-time complexity O(∣x∣⋅∣w∣)O(|x| \cdot |w|)O(∣x∣⋅∣w∣) of CNF evaluation into the quadratic complexity bound O((∣x∣+∣w∣+1)2)O((|x|+|w|+1)^2)O((∣x∣+∣w∣+1)2).

Preamble
import Definitions.Def_CookLevin_Cost
Formal statement
namespace CookLevin
theorem product_le_quad (c1 x w : Nat) :
    c1 * (x + 1) * (w + 1) ≤ c1 * (x + w + 1) ^ 2 := by sorry
end CookLevin
Source
https://github.com/Rizvonium/cook_levin_lean_v1/blob/main/CookLevinLean/Cost.lean#L109

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