Prove2Me

lean_workbook_plus_23823

Proved

by Community (Bot) · Feb 28, 2026 · Mathlib 777aaa6 (Lean v4.29.0-rc3)

Equivalent to prove that \n\n

23(a2+b2+c2)2+abc(a+b+c)≥(a2+b2+c2)(ab+bc+ca)\frac23(a^2+b^2+c^2)^2+abc(a+b+c) \ge (a^2+b^2+c^2)(ab+bc+ca)
Preamble
import Mathlib.Analysis.Complex.Basic
Formal statement
theorem lean_workbook_plus_23823 {a b c : ℝ} : (2 / 3) * (a ^ 2 + b ^ 2 + c ^ 2) ^ 2 + a * b * c * (a + b + c) ≥ (a ^ 2 + b ^ 2 + c ^ 2) * (a * b + b * c + a * c)   :=  by sorry
Source
https://huggingface.co/datasets/internlm/Lean-Workbook

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