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Broken paired signs — certificate

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HodgeComputer.OffPaired.certificate

by benediamond · Nov 5, 2026 · Mathlib 0df444a (Lean v4.33.1)

algebraic-geometryhodge-computeroff-paired

For q=1q=1q=1, and the fixed (F,A)(F,A)(F,A) of “Broken paired signs”, prove the existence of a rational vector field vvv with components homogeneous of degree 111 and common denominator relatively prime to FFF, satisfying F2∣A−1⋅dF(v)+F⋅div⁡(v)F^{2}\mid A-1\cdot dF(v)+F\cdot\operatorname{div}(v)F2∣A−1⋅dF(v)+F⋅div(v). Divisibility is in the localization with denominators relatively prime to FFF. There is no denominator degree bound. More details.

Preamble
import Definitions.Def_HodgeComputerOffPaired

Formal statement
theorem HodgeComputer.OffPaired.certificate :
    HodgeComputer.HasCertificate
      (n := HodgeComputer.OffPaired.n)
      HodgeComputer.OffPaired.F
      HodgeComputer.OffPaired.A
      HodgeComputer.OffPaired.d
      HodgeComputer.OffPaired.q := by
  sorry
Source
https://github.com/hodge-computer/sextics/blob/83fbf5c9a0afe9136ce4f1ed324d085a2c899bd0/data/off-paired/instance.rec
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What the Lean code literally says, in plain math · GPT-6 (OpenAI Codex; independent auditor)

The declaration asserts the following existence statement in the polynomial ring R=C[z0,z1,z2,z3,z4,z5]R=\mathbb C[z_0,z_1,z_2,z_3,z_4,z_5]R=C[z0​,z1​,z2​,z3​,z4​,z5​], with no universally quantified parameters or hypotheses. Fix F=∑i=05zi6+12z03z1z3z4+13z02z1z2z3z5+12z13z2z4z5F=\sum_{i=0}^{5}z_i^6+\tfrac12 z_0^3z_1z_3z_4+\tfrac13 z_0^2z_1z_2z_3z_5+\tfrac12 z_1^3z_2z_4z_5F=∑i=05​zi6​+21​z03​z1​z3​z4​+31​z02​z1​z2​z3​z5​+21​z13​z2​z4​z5​ and A=z03z33A=z_0^3z_3^3A=z03​z33​; the numerical parameters are n=5n=5n=5, d=6d=6d=6, and q=1q=1q=1. There exist polynomials D,Q∈RD,Q\in RD,Q∈R and a family (Ni)i=05(N_i)_{i=0}^{5}(Ni​)i=05​ of polynomials in RRR such that all of the following hold simultaneously: F≠0F\ne0F=0; FFF is homogeneous of degree 666; every monomial of AAA with nonzero coefficient has total degree 666; D≠0D\ne0D=0; DDD is homogeneous of degree rrr, where r=totalDegree⁡(D)r=\operatorname{totalDegree}(D)r=totalDegree(D); for every i∈{0,1,2,3,4,5}i\in\{0,1,2,3,4,5\}i∈{0,1,2,3,4,5}, every monomial of NiN_iNi​ with nonzero coefficient has total degree r+1r+1r+1; every polynomial dividing both FFF and DDD is a unit of RRR, that is, a nonzero constant polynomial; and the polynomial identity AD2−D∑i=05∂F∂ziNi+F(D∑i=05∂Ni∂zi−∑i=05∂D∂ziNi)=F2QA D^2-D\sum_{i=0}^{5}\frac{\partial F}{\partial z_i}N_i+F\left(D\sum_{i=0}^{5}\frac{\partial N_i}{\partial z_i}-\sum_{i=0}^{5}\frac{\partial D}{\partial z_i}N_i\right)=F^2QAD2−D∑i=05​∂zi​∂F​Ni​+F(D∑i=05​∂zi​∂Ni​​−∑i=05​∂zi​∂D​Ni​)=F2Q holds in RRR. Here all partial derivatives are formal polynomial derivatives, and the total degree of a monomial z0a0⋯z5a5z_0^{a_0}\cdots z_5^{a_5}z0a0​​⋯z5a5​​ is a0+⋯+a5a_0+\cdots+a_5a0​+⋯+a5​, with each aia_iai​ a nonnegative integer. The degree conditions on AAA and NiN_iNi​ quantify over every such exponent tuple whose coefficient is nonzero; they impose no requirement at tuples with zero coefficient, and they permit any NiN_iNi​ to be the zero polynomial. The integer degree expressions specialize to 6(1+1)−(5+1)=66(1+1)-(5+1)=66(1+1)−(5+1)=6 for AAA and r+6⋅1−5=r+1r+6\cdot1-5=r+1r+6⋅1−5=r+1 for each NiN_iNi​, so neither specified degree is negative. The degree rrr has no prescribed upper bound and may be 000, so a nonzero constant denominator is included among the possible witnesses. The witness QQQ is an arbitrary polynomial subject to the displayed identity, with no separately imposed degree, homogeneity, or nonzero condition; in particular, Q=0Q=0Q=0 is permitted. The witnesses are asserted to exist, with no uniqueness requirement.

Human review
  • Endorsed by Shuze Chen · Nov 6, 2026

    Confirmed by the moderator at approval.

  • Endorsed by benediamond · Nov 6, 2026

    Confirmed by the mission captain (proposal self-audit).

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