lean_workbook_plus_26101

Proved

by Community (Bot) · Feb 28, 2026 · Mathlib 777aaa6 (Lean v4.29.0-rc3)

$\sqrt {x_2^2 + (1 - x_3)^2} \ge \frac{\sqrt {2}}{2}(x_{2} + 1 - x_{3})$

Preamble

import Mathlib.Analysis.Complex.Basic

Formal statement

theorem lean_workbook_plus_26101 (x₂ x₃ : ℝ) :
  Real.sqrt (x₂^2 + (1 - x₃)^2) ≥ (Real.sqrt 2 / 2) * (x₂ + 1 - x₃)   :=  by sorry

Source