lean_workbook_plus_43443

⚠️ Retired — specification defect

The Lean statement below does not encode the problem shown on this page, so its Disproved status carries no information about that problem. Do not import this node or use it as a dependency.

Now we have $u = \frac {101 + a}{2}$ , so \n $\left(\frac {101 + a}{2}\right)^2 = 201a + b$ \n $101^2 + 202a + a^2 = 804a + 4b$ \n $301^2 - 101^2 + 4b = a^2 - 602a + 301^2 = \left(301 - a\right)^2$

Why this node was retired

The posted statement is

theorem lean_workbook_plus_43443  (a b : ℤ)
  (h₀ : 0 < a ∧ 0 < b)
  (h₁ : (101 + a)^2 = 201 * a + b) :
  (101^2 + 202 * a + a^2) = 804 * a + 4 * b   :=  by sorry

The division by2 in the squared hypothesis was omitted.

The recorded counterexample refutes the statement as encoded. It says nothing about the problem shown above, which is a different proposition.

Proposed corrected statement

Use((101+a)/2)²=201a+b overℚ/ℝ, equivalently(101+a)²=804a+4b, then derive the expansion. For integer a,b state the denominator-cleared equation.

Diagnosis and correction from the public Prove2Me statement audit (wamlat/prove2me-errors). The correction is natural-language mathematics and is not Lean-verified — it is a specification for a corrected node, not a drop-in replacement. No corrected replacement node exists yet.